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3 years ago

-16 - 3|2x - 5|2 -49

Mathematics

1 answer:

omeli [17]3 years ago

7 0

Answer:

2 x = 5 2x=5 2x=5. 2x=5. 2x=5. 2x=5. 1. Divide both sides by 2 2 2. x = 5 2 x=\frac{5}{2} x=25. Done. Decimal Form: 2.5. Check Answer ▽. x=5/2.

Step-by-step explanation:

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Find the value of x and y

Darina [25.2K]

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$\\ \rm\Rrightarrow x=2(3)$

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And

$\\ \rm\Rrightarrow \dfrac{y}{2}+1=3$

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$\\ \rm\Rrightarrow y=2(2)$

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3 years ago

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Joey completed 3,556 push ups over a 4-week period (there are 7 days in a week). Joey did the same number of push-ups every day.

wel

Answer:

127 per day

Step-by-step explanation:

Total pushups in 4 weeks = 3,556

4-week period( 7 days a week) = 4 × 7

= 28 days

How many push-ups did Joey do each day?

Push ups per day = Total push ups / Total number of days

= 3,556 / 28

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3 years ago

What is the slope of any line perpendicular to y=-1/3x+22

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Answer:
The slope of any line perpendicular to the given line is 3

Explanation:
The general form of the linear line is:
y = mx + c where m is the slope
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y = -1/3 x + 22
Comparing the given line with the general form, we will find that:
slope of the given line (m1) is -1/3

Now, for any two lines to be perpendicular, the product of their slopes should be equal to -1.
This means that:
m1 * m2 = -1
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Therefore:
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Hope this helps :)

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3 years ago

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sasho [114]

Answer:

b) 690 - 7.5*t

c) 0 < t < 92s time (t) is independent quantity

d) 0 < s < 690ft distance from bus stop (s) is dependent quantity

e) f(0) = 690 ft away from bus stop , f(60.25) = 238.125 ft away from bus stop

Step-by-step explanation:

Part a - see diagram

part b

initial distance from bus stop s0 = 690 ft

distance covered = 7.5*t

s = s0 - distance covered

s = 690 - 7.5*t = f(t)

part c

s = 0 or s = 690

0 = 690 -7.5*t

t = 92 s

Hence domain : 0 < t < 92s time (t) is independent quantity

part d

s = 0 or s = 690

Hence range : 0 < s < 690ft distance from bus stop (s) is dependent quantity because it depends on time (t)

part e

f(0) is s @t = 0

f(0) = 690 ft away from bus stop

f(60.25) is s @t = 60.25

f(60.25) = 690 - 7.5*60.25 = 238.125 ft away from bus stop.

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42/6 = 7! Happy to help

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