6th grade distributive property page 2 only 2 questions
2 answers:
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First you need to find the area of the whole circle.
The radius is given as 10, so just insert 10 into the equation of the area of a circle equation.
Putting
after the 100 because that is what is commonly done.
Because the circle is then being split into 4 equal sections, we need to find 1/4 of the area of the whole circle to find the area of one of these sections.
Since the area of the whole circle is
then we just divide that by 4,
leaving us with 25 and that is our final answer
The radius is given as 10, so just insert 10 into the equation of the area of a circle equation.
Putting
Because the circle is then being split into 4 equal sections, we need to find 1/4 of the area of the whole circle to find the area of one of these sections.
Since the area of the whole circle is
leaving us with 25
Answer:
α ≈ 76°
Step-by-step explanation:
The vertices of a rectangle are right , that is 90°
Using the tangent ratio in right triangle ABC
tanα = =
=
= 4, then
α = (4) ≈ 76° ( to the nearest degree )
Answer:
m=1/300 du
Step-by-step explanation:
we have that m=∫∫rho(x,y)dA for this we must find the limits of integration (according to the graph1)
On the x axis: if y=2x and x+2y=1 then y=2x and y=(1-x)/2 ⇒ 2x=(1-x)/2 ⇒ 4x=1-x ⇒ 5x=1 ⇒ x=1/5; on the y axis y=0 and y=1/2
m=∫∫rho(x,y)dA (view the graph 2)
