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3 years ago

Plz help me WILL GIVE BRAINLIEST

Mathematics

2 answers:

Mkey [24]3 years ago

8 0

Factor 3x^3−12x

3x^3−12x

=3x(x+2)(x−2)

Answer:

3x(x+2)(x−2)

Ganezh [65]3 years ago

3 0

3x^3 - 12x //Common factor: 3x

3x (x^2 - 4)

3x (x - 2) (x + 2)

Answer: C

//Hope this helps.

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Using the given zero, find one other zero of f(x). Explain the process you used to find your solution. 1-6i is a zero of f(x) =

Juliette [100K]

The Complex conjugate root theorem states that if a-bi is a solution, so is a+bi, and vice versa. Therefore, 1+6i is another solution

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3 years ago

Jamar draws three pairs of parallel lines that are each intersected by a third line. In each figure, he measures a pair of angle

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1 is not true generally, while 3 and 4 are never true. 2 is the only generally true conjecture.

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3 years ago

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Suppose a simple random sample of size 50 is selected from a population with σ=10σ=10. Find the value of the standard error of t

bogdanovich [222]

Answer:

a) $\sigma_{\bar x} = 1.414$

b) $\sigma_{\bar x} = 1.414$

c) $\sigma_{\bar x} = 1.414$

d) $\sigma _{\bar x} = 1.343$

Step-by-step explanation:

Given that:

The random sample is of size 50 i.e the population standard deviation =10

Size of the sample n = 50

a) The population size is infinite;

The standard error is determined as:

$\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}$

$\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}$

$\sigma_{\bar x} = 1.414$

b) When the population size N= 50000

n/N = 50/50000 = 0.001 < 0.05

Thus ; the finite population of the standard error is not applicable in this scenario;

Therefore;

The standard error is determined as:

$\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}$

$\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}$

$\sigma_{\bar x} = 1.414$

c) When the population size N= 5000

n/N = 50/5000 = 0.01 < 0.05

Thus ; the finite population of the standard error is not applicable in this scenario;

Therefore;

The standard error is determined as:

$\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}$

$\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}$

$\sigma_{\bar x} = 1.414$

d) When the population size N= 500

n/N = 50/500 = 0.1 > 0.05

So; the finite population of the standard error is applicable in this scenario;

Therefore;

The standard error is determined as:

$\sigma _{\bar x} = \sqrt{\dfrac{N-n}{N-1} }\dfrac{\sigma}{\sqrt{n} } }$

$\sigma _{\bar x} = \sqrt{\dfrac{500-50}{500-1} }\dfrac{10}{\sqrt{50} } }$

$\sigma _{\bar x} = 1.343$

7 0

3 years ago

Approximtely how many 27cubic volume cabinets will a container98,000cbic volume hold?

babymother [125]

Answer: 3630

Step-by-step explanation:

Given that:

Volume of container = 98,000 cubic volume

Volume of cabinet = 27 cubic volume

The number of cabinets which the container will. Hold equals:

Volume of container / volume of cabinet

= 98000 cubic volume / 27 cubic volume

= 3629.6296

The container will hold approximately 3630 27 cubic volume of cabinet.

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3 years ago

What is y=7x-10 y=-3

grin007 [14]

-3=7x -10
-7x=-10+3
-7x=-7
x=1

8 0

3 years ago

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