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ziro4ka [17]
3 years ago
10

In the figure below, if sin x= 5/13, what are cos x and tan x? PLZ HELP FOR THE LOVE OF GOD AND WHTS GOOD IN THE WORLD HELPPP

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

Step-by-step explanation:

cos²<em>x</em> = 1-sin²<em>x</em> = 1-(5/13)² = 144/169

cos<em>x</em> = √(144/169) = 12/13

tan<em>x</em> = sin<em>x</em>/cos<em>x </em>= (5/13)/(12/13) = (5/13)×(13/12) = 5/12

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matrenka [14]
Answer is b because the veritable is just 1 but the 4 stays the same
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3 years ago
A landscaper is selecting two trees to plant. He has five to choose from. Three of the five are deciduous and two are evergreen.
ICE Princess25 [194]

Answer:

The probability that he chooses trees of two different types is 30%.

Step-by-step explanation:

Given that a landscaper is selecting two trees to plant, and he has five to choose from, of which three of the five are deciduous and two are evergreen, to determine what is the probability that he chooses trees of two different types must be performed the following calculation:

3/5 x 2/4 = 0.3

2/5 x 3/4 = 0.3

Therefore, the probability that he chooses trees of two different types is 30%.

4 0
2 years ago
Read 2 more answers
1. Each row in a window display of floppy disk cartons contains two more boxes than the row above. The first row has one box. a.
Oduvanchick [21]
Each row has two more boxes than the row above. The first row has one box 

The boxes in a row form an arithmetic sequence with the first term, a₁ = 1 and the common difference, d=2.
The n-th term is
a_{n} = a+(n-1)d
The sum of n terms is
S_{n} = \frac{n}{2}(a_{1} + a_{n})

Answer:
The table will have the following:

Row Number:                        1   2   3    4    5    6
Boxes in the row:                  1   3   5    7    9    11
Total boxes in the display:    1   4   9  16  25  36
8 0
3 years ago
You and four friends plan a surprise party. Each of you contributes the same amount of money m for food. Write an algebraic expr
professor190 [17]

Answer:

y=x/4

Step-by-step explanation:

i don't know if this is right but i hope this helps :)

8 0
3 years ago
A recent Gallup poll found that 36% of U.S. teens aged from 13 to 17 years old have a computer with [(6)] Internet access in the
In-s [12.5K]

Answer:

Step-by-step explanation:

a) The population parameter is the population proportion.

b) Confidence interval is written as

Sample proportion ± margin of error

Margin of error = z × √pq/n

Where

z represents the z score corresponding to the confidence level

p = sample proportion. It also means probability of success

q = probability of failure

q = 1 - p

p = x/n

Where

n represents the number of samples

x represents the number of success

From the information given,

n = 1028

p = 36/100 = 0.36

q = 1 - 0.36 = 0.64

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.99 = 0.1

α/2 = 0.01/2 = 0.005

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.05 = 0.995

The z score corresponding to the area on the z table is 2.58. Thus, confidence level of 99% is 2.58

Therefore, the 99% confidence interval is

0.36 ± 2.58 × √(0.36)(0.64)/1028

The lower limit of the confidence interval is

0.36 - 0.039 = 0.321

The upper limit of the confidence interval is

0.36 + 0.039 = 0.399

Therefore, with 99% confidence interval, the proportion of U.S. teens aged from 13 to 17 years old that have a computer with Internet access in their rooms is between 0.321 and 0.399

c) for a margin of error of 1%, that is 1/100 = 0.01, then

0.01 = 2.58 × √(0.36)(0.64)/n

0.01/2.58 = √0.2304/n

0.00387596899 = √0.2304/n

Square both sides

0.00001502314 = 0.2304/n

n = 0.2304/0.00001502314

n = 15336

5 0
3 years ago
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