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ziro4ka [17]
2 years ago
10

In the figure below, if sin x= 5/13, what are cos x and tan x? PLZ HELP FOR THE LOVE OF GOD AND WHTS GOOD IN THE WORLD HELPPP

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
4 0

Answer:

Step-by-step explanation:

cos²<em>x</em> = 1-sin²<em>x</em> = 1-(5/13)² = 144/169

cos<em>x</em> = √(144/169) = 12/13

tan<em>x</em> = sin<em>x</em>/cos<em>x </em>= (5/13)/(12/13) = (5/13)×(13/12) = 5/12

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PLEASE HELP ASAP!!!
Dafna1 [17]

Answer:

Step-by-step explanation:

Any time you have compounding more than once a year (which is annually), unless we are talking about compounding continuously, you will use the formula

A(t)=P(1+\frac{r}{n})^{(n)(t)}

Here's what we have:

The amount after a certain time that she has in the bank is 4672.12; that's A(t).

The interest rate in decimal form is .18; that's r.

The number of times the interest compounds is 12; that's n

and the time that the money is invested is 3.5 years; that's t.

Filling all that into the formula:

4672.12=P(1+\frac{.18}{12})^{(12)(3.5)} Simplifying it down a bit:

4672.12=P(1.015)^{42} Raise 1.015 to the 42nd power to get

4672.12 = P(1.868847115) and divide to get P alone:

P = 2500.00

She invested $2500.00 initially.

6 0
3 years ago
Help plz I need asap
miv72 [106K]
Choose the one on the very top.
6 0
2 years ago
Answer this please!​
Troyanec [42]

f(x) = 4x + 3

That's one-to-one, a linear function that will give a different f(x) for each different x.

For the inverse let's swap x and y and solve for y

x = 4y + 3

x - 3 = 4y

y = (x- 3)/4

That's the inverse,

Answer:  (x- 3)/4, second choice

The domain and range of the inverse is all real numbers.  It's two lines; I'll leave the graphing to you.

8 0
3 years ago
WILL GIVE BRAINLIEST!!!!!!! Kate has 4 feet of rope. She cuts the rope into pieces that are each
Delvig [45]
<h2>Answer:</h2>

7

<h2>Step-by-step explanation:</h2>

4 1/5 ÷ 3/5 = 7

Kate cut 7 pieces of rope.

<h2>#BrainliestAnswer</h2><h2>#CarryOnLearning</h2>
5 0
2 years ago
Simplify x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2
Artemon [7]

Answer:

2x^2 + 2y^2 + 2z^2

Step-by-step explanation:

x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2

First step is to put all the same ones together

( FYI, xy and yx is the same thing, just like how

2 x 3 and 3 x 2 is the same thing) this time I'll bracket the groups to make it easier on the eyes

(x^2 +x^2) + (xy - xy) +( y^2 + y^2) + (yz - yz) +

(z^2 +z^2) + (zx - zx)

2x^2 + 2y^2 + 2z^2

All the others just cancel themselves out, for example, xy-xy

When anything minus themselves it will become 0

7 0
3 years ago
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