I hope this is the answer you want
Answer:
Graph of quadratic opening downward and linear sloping up to the left. They intersect at point negative 3, negative 1 and point 1, negative 5
Step-by-step explanation:
we have
we can separate the expression above into two equations
----> equation A
This is a quadratic equation ( vertical parabola) open downward (the leading coefficient is negative)
----> equation B
This is a linear equation with negative slope (decreasing function).so linear sloping up to the left
The solution of the original expression are the x-coordinates of the intersection point both graphs
using a graphing tool
The intersection points are (-3,-1) and (1,-5)
see the attached figure
Answer:
c² - 63
Step-by-step explanation:
4c - 10 = 30
3c ÷ 3 = 10
c² - 63 = 37
c² ÷ 10 = 10
Since c² - 63 = 37 and c + 25 = 35, 37 is greater than 35 so it would make sense to choose c² - 63 as the answer.
c + 25 < 37
I hope this helps you :D
100p = £1
so
so you multiply T by 100 to get the value in pence
100T = £T
Answer:
Below.
Step-by-step explanation:
f) (a + b)^3 - 4(a + b)^2
The (a+ b)^2 can be taken out to give:
= (a + b)^2(a + b - 4)
= (a + b)(a + b)(a + b - 4).
g) 3x(x - y) - 6(-x + y)
= 3x( x - y) + 6(x - y)
= (3x + 6)(x - y)
= 3(x + 2)(x - y).
h) (6a - 5b)(c - d) + (3a + 4b)(d - c)
= (6a - 5b)(c - d) + (-3a - 4b)(c - d)
= -(c - d)(6a - 5b)(3a + 4b).
i) -3d(-9a - 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b).
= (3d + 2c)(9a + 2b).
j) a^2b^3(2a + 1) - 6ab^2(-1 - 2a)
= a^2b^3(2a + 1) + 6ab^2(2a + 1)
= (2a + 1)( a^2b^3 + 6ab^2)
The GCF of a^2b^3 and 6ab^2 is ab^2, so we have:
(2a + 1)ab^2(ab + 6)
= ab^2(ab + 6)(2a + 1).
