X=27 and y=11
if you let each number equal x and y we know the sum is 38 so x+y=38
and the smaller is 16 less than the larger
. so if we say the smaller number is 7 then x-16=y
these can be solved as a simultaneous equation. x+(x-16)=38
2x-16=38
2x=54
x=27
(27)-16=y
y=11
so the answer is x=27 y=11
Answer:
a.240.15
Step-by-step explanation:
a.240.15
b.12.0075
c.252.1575
10 + f = 10
-10 -10
f = 10 - 10
f = 0.
Answer: -2 and 26
Step-by-step explanation:
-2 * 26 = -52
-2 + 26 = 24
