Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
6.
Intersecting chords:
RT x ST = PT x TQ
2 x 6 = 3 x TQ
12 = 3TQ
TQ = 12/3
TQ = 4
7.
AD = 90 -BE = 90-18 = 72
ADE = 180. DE = 180 - AD = 180-72 = 108
AE = 180. AB = 180-18 = 162
DE = 108
BD = BE +DE = 18 + 108 = 126
DAB = 72 + 162 = 234
ADE = 90 degrees
8.
AB^2 = BC* (BC +x)
8^2 = 2 * (2 +x)
64 = 4 + 2x
60 = 2x
X = 60/2
X = 30
Answer:
Mean of the data set in the dot plot would be: 3.6
Step-by-step explanation:
As we know that Mean from the dot plot can be obtained by:
- adding the numbers and then
- divide the resulting sum by the number of addends.
Please check the attached figure where the dot plot is also plotted.
From the dot plot, it is clear that
There are 3 dots at 1.
There are 4 dots at 2.
There are 3 dots at 3.
There are 4 dots at 4.
There are 5 dots at 5.
There are 3 dots at 6.
All we have to do is to add the dots and divide the sum by the number of addend dots.
In other words:
There are 3 dots at 1 ⇒ 1+1+1
There are 4 dots at 2 ⇒ 2+2+2+2
There are 3 dots at 3 ⇒ 3+3+3
There are 4 dots at 4 ⇒ 4+4+4+4
There are 5 dots at 5 ⇒ 5+5+5+5+5
There are 3 dots at 6 ⇒ 6+6+6
As there are total 22 dots.
And the sum of all the dots with respect to their plot number = 79
i.e. 1+1+1+2+2+2+2+3+3+3+4+4+4+4+5+5+5+5+5+6+6+6 = 79
Thus
Mean of the data set in the dot plot = 79/22
= 3.6
Therefore, Mean of the data set in the dot plot would be: 3.6
Answer:
Step-by-step explanation:
4x/2= -5
4x= -5*2
2x= -5
x= -5/2
Answer:
What are the options?
Step-by-step explanation: