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-Dominant- [34]
2 years ago
12

You drop a pencil out of window that is 20ft above the ground. Use the formula V^2=64s, where V is speed and s is the distance f

allen, to calculate the speed the pencil is traveling when it hits the ground.
Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
8 0
First you substitute in the values so you have
V^2=(64)20
then you just simplify it
V^2=1280
V=the square root of 1280
V= about 35.7770876
or
V=the square root of 256 times <span>the square root of 5
V=16 times </span><span>the square root of 5

also V would typically be called velocity. it's very similar to speed but it is just easier to remember because it starts with a V</span>
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Slope -1/4, passes through (12,-4)​
Kazeer [188]

Answer:

y = - \frac{1}{4} x - 1

Step-by-step explanation:

Assuming you require the equation of the line

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{1}{4} , then

y = - \frac{1}{4} x + c ← is the partial equation

To find c substitute (12, - 4) into the partial equation

- 4 = - 3 + c ⇒ c = - 4 + 3 = - 1

y = - \frac{1}{4} x - 1 ← equation of line

7 0
2 years ago
Sin(x)=−1 how do you solve this
Zanzabum

Answer:

you can't

Step-by-step explanation:

6 0
3 years ago
Heyy could you help me out with this problem???​
Elan Coil [88]

Answer:

not sure

Step-by-step explanation:

sorry :/

7 0
2 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
PLZ HELP WILL GIVE BRAINLIEST 50+25 POINTS!!!<br><br>Graph the following piecewise function.
Luda [366]

We need to graph the given piecewise function.

To graph any piecewise function we do that into parts

Let's graph upper part first which is

f(x)=x^2+2

restriction for that is -5 \leq x < 3

that means we are free to pick any number for x that is between -5 and 3, including 3.

So we will find few points by plugging random numbers between -5 and 3.

Let's use x=-5, we get:

f(-5)=(-5)^2+2=25+2=27

so first point is (-5,27).

similarly we can find other points like (0,2), (2,6), (-1,3) etc.

Now we join those points by a curved line.

-5 \leq x means we use a close circle at -5

x<3 means use open circle at 3


------------

Repeat same process for 2nd part f(x)=x-4

choose any number between 3 and 7 like x=3, 4 etc

so we get points (3,-1), (4,0) etc

Now graph them

So the final graph will look like:


5 0
2 years ago
Read 2 more answers
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