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NNADVOKAT [17]
3 years ago
13

What is the solution to the equation m/m+4 +4/4-m = m^2/ m^2- 16 ?

Mathematics
2 answers:
nignag [31]3 years ago
7 0
The answer is 2 i think
iris [78.8K]3 years ago
6 0

Answer:

answer is c on edge 2021

Step-by-step explanation:

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Use distributive law to expand the following.<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%20%28%5Csqrt%7B2%7D%20%2B%5Cs
balu736 [363]

Answer:

√6 + √15

Step-by-step explanation:

√3(√2 + √5)=√3√2+√3√5

                    = √6 + √15

7 0
3 years ago
Of you give me the equation I can probably solve it but I can't figure it out PLZ HELP!!!
Komok [63]

Answer:

($4.30 × 3)(3c) = $19.50

c = $2.20

Step-by-step explanation:

($4.30 × 3)(3c) = $19.50

(12.90)(3c) = 19.50

3c = 6.60

c = 2.20

(u had most of the equation laid out already, u were just missing 3c)

4 0
3 years ago
Read 2 more answers
A normal distribution in which approximately 68% of the data values fall within one standard deviation of the mean behaves accor
Komok [63]
That's the empirical rule.  Very useful!

3 0
4 years ago
Use generating functions to determine the number of different ways 15 identical stuffed animals can be given to six children so
Tresset [83]

Answer:

50

Step-by-step explanation:

4 0
3 years ago
Can someone please help me understand Exponential Growth and Decay please?
Temka [501]

Exponential word problems almost always work off the growth / decay formula, <span>A = Pert</span>, where "A" is the ending amount of whatever you're dealing with (money, bacteria growing in a petri dish, radioactive decay of an element highlighting your X-ray), "P" is the beginning amount of that same "whatever", "r" is the growth or decay rate, and "t<span>" is time. The above formula is related to the </span>compound-interest formula, and represents the case of the interest being compounded "continuously".

Note that the variables may change from one problem to another, or from one context to another, but that the structure of the equation is always the same. For instance, all of the following represent the same relationship:

<span>A<span> = </span><span>Pe<span>r<span>t   </span></span></span></span>...or...   <span>A<span> = </span><span>Pe<span>kt</span></span></span><span>   ...or...   </span><span>Q<span> = </span>Ne<span>kt</span></span><span>   ...or...   </span><span><span>Q<span> = </span>Q</span>0<span>e<span>kt</span></span></span>

<span>...and so on and so forth. No matter the particular letters used, the green variable stands for the ending amount, the blue variable stands for the beginning amount, the red variable stands for the growth or decay constant, and the purple variable stands for time. Get comfortable with this formula; you'll be seeing a lot of it.</span>

I hope this is useful !!!^_~!!!

8 0
3 years ago
Read 2 more answers
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