Answer:
Randy has eight $5 bills and nine $1 bills
Step-by-step explanation:
Randy needs $50.00
And we know that he his only $1.00 short, so he has $49.00
let's define:
x = number of $1 bills that he has
y = number of $5 bills that he has.
then:
x*$1 + y*$5 = $49
We know that he has one more $1 bills than $5 bills.
we can write this as
x = y + 1
So we have a system of two equations and two variables:
x*$1 + y*$5 = $49
x = y + 1
First we can see that the variable "x" is isolated in the second equation, now we can replace that in the other equation:
x*$1 + y*$5 = $49
(y + 1)*$1 + y*$5 = $49
now we can solve this for y.
y*$1 + $1 + y*$5 = $49
y*($1 + $5) = $49 - $1 = $48
y*$6 = $48
y = $48/$6 = 8
He has 8 $5 bills
and we know that:
x = y + 1
x = 8 + 1 = 9
he has 9 $1 bills.
2x^2 + 3xy - 4y^2 when x = 2 and y = -4
= 2(2)^2 + 3(2)(-4) - 4(-4)^2 = 2(4) + (-24) - 4(16) = 8 - 24 - 64 = -80
Answer:
1/12
Step-by-step explanation:
1/3 times 1/4 is 1/12
Answer:
B. Arithmetric
Step-by-step explanation:
Answer:
Alright so the Answer to this question is
x = 3, - 7 Why? because you have to move all terms to the left side and set equal to zero, then set each factor equal to zero Hope this helps :)
Step-by-step explanation:
