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3 years ago

The price of a new car was 12500 it is reduced 11625 work out the percentage reduction

Mathematics

2 answers:

Travka [436]3 years ago

8 0

Answer:

The price is reduced 7%; its new price is 93% of the old price.

Step-by-step explanation:

The price is reduced from 12500 to 11625. This is a decrease of

12500-11625 = 875.

To find the percent of decrease, divide the amount of decrease by the original amount:

875/12500 = 0.07 = 7%

This means the price was reduced 7%, and the current price is 100-7 = 93% of the old price.

mart [117]3 years ago

6 0

% Decrease = Decrease ÷ Original Number × 100

Divde 11,625 by 12,500 and multiply the answer by 100.

11,625 ÷ 12,500 × 100 = 93

The percentage reduction is 93%.

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Solution:

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$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

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$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

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