All categories

3 years ago

The price of a new car was 12500 it is reduced 11625 work out the percentage reduction

Mathematics

2 answers:

Travka [436]3 years ago

8 0

Answer:

The price is reduced 7%; its new price is 93% of the old price.

Step-by-step explanation:

The price is reduced from 12500 to 11625. This is a decrease of

12500-11625 = 875.

To find the percent of decrease, divide the amount of decrease by the original amount:

875/12500 = 0.07 = 7%

This means the price was reduced 7%, and the current price is 100-7 = 93% of the old price.

mart [117]3 years ago

6 0

% Decrease = Decrease ÷ Original Number × 100

Divde 11,625 by 12,500 and multiply the answer by 100.

11,625 ÷ 12,500 × 100 = 93

The percentage reduction is 93%.

You might be interested in

The number of decimal places in the product will be sum of the factor"s decimal place.So the product will have 1,2,3 or 4 decima

vampirchik [111]

Answer:

$0.47 \to 2\ digits$

$3.2 \to 1\ digit$

$Product \to 3\ digits$

Step-by-step explanation:

Given

$0.47 * 3.2 =$

See comment for complete question

Required

The number of decimal places

To do this, we simply calculate the number of digits after the decimal points

$0.47 \to 2\ digits$

$3.2 \to 1\ digit$

The product is the sum of the digits above 2 + 1 = 3

Hence:

$Product \to 3\ digits$

6 0

3 years ago

I'm studying a new bacteria that doubles in numbers every 25 minutes. If i start with 50 bacteria, how long until i have 5 milli

dimaraw [331]

Answer:

415.63 minutes

Step-by-step explanation:

Growth can be represented by the equation $A=A_0e^{rt}$ . We can find the rate at which it grows by using t=25 minutes and $\frac{A_{0}}{A} =2$ or double the amount at that time. The first step we always take is to divide $A_0$ by A.

$[tex]\frac{A_{0}}{A}=e^{rt}\\2=e^{r(25)}$

$2=e^{(25)r}$

To solve for r, we will take the natural log of both sides and use log rules to isolate r.

$ln 2=ln e^{(25)r}\\ln 2=25r (ln e)\\\frac{ln2}{25} =r$

We know $lne=1$ so we were able to cancel it out and divide both sides by 25.

We solve with a calculator $\frac{ln2}{25} =r\\0.0277=r$

We change 0.0277 into a percent by multiplying by 100 to get 2.77% as the rate.

The equation is $A=A_0e^{0.0277t}$ .

We repeat the step above substituting A=5,000,000, $A_0$ =50, and r=0.02777. Then solve for t.

$5000000=50e^{0.0277t}\\\frac{5000000}{50} =e^{0.0277t}\\100000=e^{0.0277t}\\ln100000=lne^{0.0277t}\\ln100000=0.02777t(lne)\\\frac{ln100000}{0.0277} =t$