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Mars2501 [29]
3 years ago
11

Prove algebraically that the recurring decimal 0.472 can be written as 17 36

Mathematics
1 answer:
Katen [24]3 years ago
8 0

Given:

The recurring decimal is 0.47\overline{2}.

To prove:

Algebraically that the recurring decimal 0.47\overline{2} can be written as \dfrac{17}{36}.

Proof:

Let,

x=0.47\overline{2}

x=0.472222...

Multiply both sides by 100.

100x=47.2222...     ...(i)

Multiply both sides by 10.

1000x=472.2222...        ...(ii)

Subtract (i) from (ii).

1000x-100x=472.2222...-47.2222...

900x=425

Divide both sides by 900.

x=\dfrac{425}{900}

x=\dfrac{17}{36}

So, 0.47\overline{2}=\dfrac{17}{36}.

Hence proved.

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4 0
3 years ago
What is the greatest common factor (GCF) of the numerator and denominator
ad-work [718]

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4 0
3 years ago
Read 2 more answers
14(0.89)^x+4.5 =162
lisabon 2012 [21]
14(0.89)^{x + 4.5} = 162
\frac{14(0.89)^{x + 4.5}}{14} = \frac{162}{14}
0.89^{x + 4.5} = 11\frac{4}{7}
ln(0.89^{x + 4.5}) = ln(11\frac{4}{7})
(x + 4.5)ln(0.89) = ln(11\frac{4}{7})
\frac{(x + 4.5)ln(0.89)}{ln(0.89)} = \frac{ln(11\frac{4}{7})}{ln(0.89)}
x + 4.5 = -2101.14032500
x = 2105.64032500
3 0
3 years ago
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