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kap26 [50]
2 years ago
12

Where is 0.15 on a number line

English
2 answers:
Alex2 years ago
5 0
0.15 is between 0.14 and 0.16 on a number line.

SpyIntel [72]2 years ago
4 0
It is .... between 0.14 and 0.16. 
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3 years ago
Fernando evaluated the expression below. StartFraction 5 (9 minus 5) over 2 EndFraction + (negative 2) (negative 5) + (negative
Juli2301 [7.4K]

Question:

Fernando evaluated the expression below.

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{5(4)}{2} -10 + 9 = \frac{20}{2} - 10 + 9 = 10 - 10 + 9 = 9

What was Fernando's error?

- Fernando evaluated the numerator of the fraction incorrectly.

- Fernando simplified 20/2 incorrectly.

- Fernando incorrectly found the product of –2 and –5.

- Fernando evaluated (-3)² incorrectly.

Answer:

- Fernando incorrectly found the product of –2 and –5.

Explanation:

Given

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{5(4)}{2} -10 + 9 = \frac{20}{2} - 10 + 9 = 10 - 10 + 9 = 9

Required

Spot the error

The error in this evaluation is the product of -2 and -5 at step 2

When a negative number (-2) is multiplied by a negative number (-5), the outcome of the multiplication is always a positive number (10).

So, the result of -2 * -5 is 10 but Fernando incorrectly calculated it as -10.

Solving the expression, correctly

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{5(4)}{2} + 10 + 9

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{20}{2} + 10 + 9

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = 10 + 10 + 9

\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = 29

Hence, the actual result of the expression is 29 (not 9 as calculated by Fernando).

7 0
3 years ago
Read 2 more answers
PROMPT:
kramer

Explanation:

Yeah so I made something but it wouldn't copy over and I lost it :((((((( I am so sorry!

your thesis should be along these lines tho: Immigrant communities generally find comfort in familiar religious traditions and rituals, seek out newspapers and literature from the homeland, and celebrate holidays and special occasions with traditional music, dance, cuisine, and leisure-time pursuits.

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