The solubility of NaCl in water will not be affected by an increase in pressure.
We know that the density of NaCl(s) in 2.165 g/cm³ at 25 °C and we want to know how will its solubility in water be affected when the pressure is increased.
<h3>What is solubility?</h3>
Solubility is the maximum mass of a solute that can be dissolved in 100 grams of solvent at a determined temperature.
The solubility of a solid, such as NaCl, in a liquid, is mainly affected by the temperature. However, since solids are not compressible, an increase in pressure will not affect its solubility.
On the other hand, the solubility of gases in water will increase with an increase in pressure, as stated by Henry's law.
The solubility of NaCl in water will not be affected by an increase in pressure.
Learn more about solubility here: brainly.com/question/11963573
L=0 s
l=1 P
l=2 d
The answer is d.
Answer:
See Explanation Note ...
Explanation:
Depending on amount added, Anhydrous CaCl₂ when dissolved in water solvent can become hot enough to blister ones skin when touched. On the cold side, Ammonium Nitrate will cool an aqueous solution enough to generate condensate frost on the outside of a glass beaker. I'm sure there are more examples but these two came to mind.
5.82x10small 2 on the top of the ten like a exponent
Answer:
wavelength (λ) = 2.73 E-4 m
frecuency (f) = 1.10 E12 s-1
Explanation:
Stefan-Boltzmann law:
- intensity of the radiation for a black body (W) = σ.(T)∧4
∴ σ = 5.670 E-8 W/m²(K)∧4
∴ T = 298 K
⇒ W = (5.670 E-8 W/m²K∧4)×(298 K)∧4
⇒ W = 447.145 W/m² = 447.145 J/s.m²
assuming an area of 1 m²
⇒ W = 447.145 J/s
Rayleigh-Jeans's law:
∴ Black body radiation at a specific wavelength (Bλ(T)):
⇒ Bλ(T) = ( 2 c.k.T ) / (λ)∧4
∴ c = 3 E8 m/s.....velocity of speed
∴ k = 1.38065 E -23 J/K.........Boltzmann's constant
∴ Bλ(T) = 447.145 J/s.m²
⇒ (λ)∧4 = ((2)(3 E8 m/s)(1.38065 E-23 J/K)(298 K)) / (447.145 J/s)
⇒ λ = (5.521 E-15)∧(1/4)
⇒ λ = 2.73 E-4 m
⇒ f = (3 E8 m/s) / (2.73 E-4 m)
⇒ f = 1.10 E12 s-1