Answer:
Am not sure about my Answer but I know am correct I don't know if you have multiple options to your question. My Answer is correct but am not sure it is going to be correct for your question.
Gaining of electrons
Explanation:
Reduction is the gain of electrons. Oxidation and reduction always occur together, even though they can be written as separate chemical equations.
Explanation:
to see how a change in a reactant concentration would affect the speed of the chemical reaction
Complete Question
The complete question is shown on the first uploaded image
Answer:
The kinetic order in HI is x= 2
Explanation:
Generally the slow step in a reaction mechanism is the rate determining step
Now with this knowledge at the back of our minds we can see that the number of moles of HI i s 2 which implies that the order of HI is 2m
So we can represent the rate law as
hence
x = 2
Answer:
12.44 g
Explanation:
2C4H10 + 13O2 = 8CO2 + 10H2O
n(C4H10) = m(C4H10)/M(C4H10) = 4.1 / 58g/mol = 0.0707 mol (excess).
n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).
Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.
mass of CO2 produced =
M = [0.0707 moles C4H10 x 8 moles CO2] / 2 moles C4H10 x 44 g CO2/mol
M = 0.5656/2 * 44
M = 0.2828 * 44
M = 12.44 of CO2
<u>Answer:</u> The internal energy change for the reaction is -2850 J
<u>Explanation:</u>
- <u>Sign convention of heat:</u>
When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.
- <u>Sign convention of work:</u>
Work done for expansion process is taken as negative and work done for compression is taken as positive.
According to the First law of thermodynamics,
where,
= internal energy
q = heat absorbed or released = -2290 J
w = work done = -560 J
Putting values in above equation, we get:
Hence, the internal energy change for the reaction is -2850 J