3 years ago

Find the y intercept of the line y+3=4(x+3)

Mathematics

1 answer:

lys-0071 [83]3 years ago

3 0

Y-Intercept is: (0,9)

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Let r(t)=⟨t2,1−t,4t⟩. calculate the derivative of r(t)⋅a(t) at t=5, assuming that a(5)=⟨−4,4,−5⟩ and a′(5)=⟨−5,9,3⟩

erastovalidia [21]

$\mathbf r(t)=\langle t^2,1-t,4t\rangle$
$\implies\mathbf r'(t)=\langle 2t,-1,4\rangle$

$\dfrac{\mathrm d(\mathbf r(t)\cdot\mathbf a(t))}{\mathrm dt}\bigg|_{t=5}=\mathbf r'(5)\cdot\mathbf a(5)+\mathbf r(5)\cdot\mathbf a'(5)$
$=\langle10,-1,4\rangle\cdot\langle-4,4,-5\rangle+\langle25,-4,20\rangle\cdot\langle-5,9,3\rangle$
$=(-40-4-20)+(-125-36+60)$
$=-165$

6 0

3 years ago

Find the area of the circle

vlada-n [284]

Answer:

A = 1.77 ft^2

Step-by-step explanation:

The circle has a diameter of 1.5 ft

We need the radius

r = d/2 = 1.5/2 = .75 ft

The area of a circle is

A = pi r^2

A = 3.14 ( .75)^2 = 1.76625

To the nearest hundredth

A = 1.77 ft^2

3 0

3 years ago

Tim's bank contains quarters, dimes and nickels. He has 3 more dimes than quarters and 6 fewer nickels than quarters. If he has

Aleksandr-060686 [28]

(x - 3) + (x - 6) + x = 63
x - 3 + x - 6 + x = 63
Combine like terms
3x - 9 = 63
Isolate the constant
3x - 9 + 9 = 63 + 9
3x = 72
Isolate the viable
3x / 3 = 72 / 3
x = 24

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2 years ago

A piston is seated at the top of a cylindrical chamber with radius 5 cm when it starts moving into the chamber at a constant spe

Tanzania [10]

Rate is change is 1.2

6 0

3 years ago

Find the equation of the line.

zhuklara [117]

Answer:

y=-1/3x-2

Step-by-step explanation:

First off, lets outline that parallel lines have the <u>Same Slope</u>. So we can plug in -1/3 as our slope, or m.

Lets plug in -1/3 as our slope in Point Slope form to find the y intercept. Point slope form should be attached in an image below.

1) Plug slope and points into point slope form:

y+1=-1/3(x+3)

2) Distribute -1/3 to x and 3:

y+1=-1/3x-1

3) Subtract 1 from both sides:

y=-1/3x-2

Now we have our answer is slope intercept form!

Please let me know if you have any questions :)

3 0

2 years ago