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Mila [183]
3 years ago
5

I have a 15ft x 36in (4.57m x 91 cm) pool and the mats i wanna buy are 20.5-in x 20.5-in. How many mats would i need to put unde

r the pool?

Mathematics
1 answer:
yuradex [85]3 years ago
4 0

Answer:

you would need 4 matts

Step-by-step explanation:

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~Please help as soon as possible~
Setler79 [48]


60/40 =5

40*5=200

Answer For 1 is 200

35/10=3.5

20*3.5=70

Answer For 2 is 70 Pounds

85/40=2.125

2.125*600

1275

Answer For 3 is 1275


5 0
3 years ago
Read 2 more answers
Help please? I can choose more than one answer I just don’t understand this stuff
Gwar [14]

...hay.... \\  a + 8 =    -  \frac{5}{a}  \\ a +  \frac{5}{a}  =  - 8 \\  {a }^{2}  + 5 =  - 8a \\  {a }^{2}  + 8a =  - 5 \\ henca \:  \: opion \: no.1 \: is \: correct
7 0
3 years ago
A bike store sells scooters at a 54% markup. If the store bought each scooter for $29.25, what is the resale price to the neares
7nadin3 [17]

The purchasing price of the store = $29.25.

They want to resale it at 54% markup of the purchasing price.

54% of 29.25 = 0.54 × 29.25.

On multiplying 0.54 and 29.25, we get 15.795.

Resale price = The purchasing price + Markup

                      = 29.25 + 15.795.

On adding 29.25 and 15.795, we get 45.045.

We can round it to 45 to the nearest dollar.

<h3>Therefore, the resale price to the nearest dollar is $45.</h3>
5 0
3 years ago
If you run for 0.4 hours at 7 mph, how fast should you walk during the next 0.8 hours to have the average speed of 5 mph?
Fantom [35]

Answer:

4 mph

Step-by-step explanation:

The average speed of an object is given by the total distance covered by the time taken:

v=\frac{d}{t}

where

d is the total distance covered

t is the time taken

in the first part, the person runs for 0.4 hours at a speed of 7 mph, so the distance covered in the 1st part is

d_1 = v_1 t_1 = (7)(0.4)=2.8 mi

Then the distance covered in the second part is d_2, so the total distance is

d=2.8+d_2 (1)

The total time elapsed is 0.4 hours (first part) + 0.8 hours (second part), so

t=0.4+0.8=1.2 h

So we can write the average speed as

v=\frac{2.8+d_2}{1.2} (1)

We want the average speed to be 5 mph,

v = 5 mph

Therefore we can rearrange eq.(1) to find d2:

d_2 = 1.2v-2.8 = (1.2)(5)-2.8=3.2 mi

And therefore, the speed in the second part must be

v_2=\frac{d_2}{t_2}=\frac{3.2}{0.8}=4 mph

4 0
2 years ago
Maya has 5 over 6 cup of ice cream. How many 1 over 4 -cup servings are in 5 over 6 cup of ice cream?
Drupady [299]
The answer is c because it’s not a or d and maybe not b so ye c
6 0
2 years ago
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