Answer:
(x+y)² =(x+y)(x+y) Then you FOIL (First, outer, inner, last)
(x+y)² =(x+y)(x+y) = xx + xy + xy + yy [and when you combine like terms] = x² + 2xy + y²
(x+y)3 = (x² + 2xy + y²)(x+y) Then you FOIL (First, outer, inner, last)
(x+y)3 = (x² + 2xy + y²)(x+y) = x2x +2xxy + xy2 + x2y + 2xyy + y2y [and when you combine like terms] = x3 + 3x2y+ 3xy2 + y3
Step-by-step explanation:
Since we want to find the value of <em>k</em><em> </em>where the limit exists, set both equations equal to each other. Then substitute <em>x</em> = -1 in for each equation to find <em>k</em><em>.</em>
<em>
</em>
1. Set both equations equal.

2. Substitute <em>x</em><em> </em>= -1.

3. Solve for <em>k</em><em> </em>by adding <em>k</em><em> </em>to both sides. Continue the process of solving the equation.


Thus, <em>k</em><em> </em>= -2. Check by graphing the function.
Part of a line but has 2 end point, extends in no direction. example: @
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:////