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Alex_Xolod [135]
2 years ago
14

Factorise:x²+30x+216​

Mathematics
2 answers:
xenn [34]2 years ago
8 0

Answer:

answer would be (x + 12)(x + 18).

Step-by-step explanation:

Let's factor x^2 + 30x + 216

x^2 + 30x + 216

Answer:

(x + 12) (x + 18)

kirill [66]2 years ago
4 0

Answer: (x + 12)(x + 18)

Step-by-step explanation: x² + 30x + 216​

                                              12 + 18 = 30

                                              12 x 18 = 216

                                              (x + 12)(x + 18)

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23 pounds is 368 ounces


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Read 2 more answers
F/4 + 16 &lt; 49<br> Solve the inequality
Mnenie [13.5K]

Answer:

f < 132

Step-by-step explanation:

Greetings!

I'm~Isabelle~Williams~and~I~will~be~answering~your~question!

Subtract~16~from~both~sides:

\frac{f}{4} +16-16 < 49-16

Simplify:

\frac{f}{4} < 33

Now,~multiply~both~sides~by~4:

\frac{4f}{4} < 33\times4

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5 0
3 years ago
Hello, can someone pls help me ty!​
max2010maxim [7]

Answer:

C, 5/2

Step-by-step explanation:

3 I2x -1I + 4 = 16

Isolate absolute value:

3 I2x -1I + 4 - 4 = 16 - 4

3 I2x -1I= 12

(3 I2x -1I) / 3 = 12 / 3

I2x -1I= 4

Since the question is only asking for the positive, all you need to solve for is the +4. Solve for x

2x -1 = 4

2x -1 + 1 = 4 +1

2x = 5

2x / 2 = 5 / 2

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7 0
3 years ago
Dinosaur fossils are often dated by using an element other than carbon, like potassium-40, that has a longer half life (in this
Firlakuza [10]
The amount of substance left of a radioactive element of half life, t_{\frac{1}{2}} after a time, t, is given by:

N(t)=N_0\left( \frac{1}{2} \right)^ \frac{t}{t_{  \frac{1}{2} }}

Given that <span>potassium-40 has a half life of approximately 1.25 billion years.

The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

0.1=100\left( \frac{1}{2} \right)^ \frac{t}{1.25}} \\  \\ \Rightarrow\left( \frac{1}{2} \right)^ \frac{t}{1.25}}=0.001 \\  \\ \Rightarrow\frac{t}{1.25}\ln\left( \frac{1}{2} \right)=\ln(0.001) \\  \\ \Rightarrow \frac{t}{1.25}= \frac{\ln(0.001)}{\ln\left( \frac{1}{2} \right)} =9.966 \\  \\ t=9.966(1.25)=12.5

Therefore, </span><span>the maximum age of a fossil that we could date using 40k is 12.5 billion years.</span>
3 0
3 years ago
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