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Likurg_2 [28]
3 years ago
12

Someone please help <3

Mathematics
1 answer:
nataly862011 [7]3 years ago
4 0

Answer:

i think there's zero solutions

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Four friends went on a trip and spent $51.20 on gas. Jackie brought $12.25. Will she be able to pay her share of gas if they spl
aleksandrvk [35]
No she won’t be able to, because her share the gas will be $12.80 and she only has $12.25
6 0
4 years ago
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For a normal distribution with a mean of 16 and a standard deviation of 3, find the 50th percentile. Can someone please explain
andrew11 [14]
The probability distribution of normal distribution is given by,

f(x) = \frac{1}{{ \sqrt{2 \pi  \alpha ^{2} } }} e^{ \frac{-(x-a)^{2} }{2 \alpha^{2} } }

Where a = mean = 16 and α = standard deviation = 3

In normal distribution, skewness is zero. That is, distribution is symmetric. 
Therefore, mean, median and mode coincide at a point in case of normal distribution.

50th percentile is same as median or mean or mode
Therefore, 50th percentile = 16
6 0
4 years ago
Given 4x − 8y = 8:
siniylev [52]
4x - 8y = 8
8y = 4x - 8
y = 1/2 x - 1

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y-intercept:(0, -1)

Line perpendicular- negative reciprocal slope

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3 0
3 years ago
Distribute - 10 (1 + 3x).
Keith_Richards [23]

Answer:

10 + 30x

Step-by-step explanation:

8 0
3 years ago
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Suppose that 4 fair coins are tossed. Let Equals The event that exactly 2 coins show tails and Equal The event that at least 2 c
faust18 [17]

Answer:

a) P ( E | F ) = 0.54545

b) P ( E | F' ) = 0

Step-by-step explanation:

Given:

- 4 Coins are tossed

- Event E exactly 2 coins shows tail

- Event F at-least two coins show tail

Find:

- Find P ( E |  F )

- Find P ( E | F prime )

Solution:

- The probability of head H and tail T = 0.5, and all events are independent

So,

                    P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT)  = 6*(1/2)^4 = 0.375

                    P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)

      = 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875

- The probabilities for each events are:

                    P ( E ) = 0.375

                    P ( F ) = 0.6875

- The Probability to get exactly two tails given that at-least 2 tails were achieved:

                    P ( E | F ) = P ( E & F ) / P ( F )

                    P ( E | F ) = 0.375 / 0.6875

                    P ( E | F ) = 0.54545

- The Probability to get exactly two tails given that less than 2 tails were achieved:

                    P ( E | F' ) = P ( E & F' ) / P ( F )

                    P ( E | F' ) = 0 / 0.6875

                    P ( E | F' ) = 0                

6 0
3 years ago
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