Answer:
The next generation average time to flowering will be 98 days.
Explanation:
Before answering the question, we need to know a few concepts.
- Artificial selection is the selecting practice of a specific group of organisms in a population -that carry the traits of interest- to be the parents of the following generations.
- Parental individuals carrying phenotypic values of interest are selected from the whole population. These parents interbreed, and a new generation is produced.
- The selection differential, SD, is the difference between the mean value of the trait in the population (X₀) and the mean value of the parents, (Xs). So,
SD = Xs - X₀
- Heritability in the narrow-sense, h², is the genetic component measure to which additive genetic variance contributes. The heritability might be used to determine how the population will respond to the selection done, R.
h² = R/SD
- The response to selection (R) refers to the metric value gained or lost from the cross between the selected parents. R can be calculated by multiplying the heritability h², with the selection differential, SD.
R = h²SD
R also equals the difference between the new generation phenotypic value (X₁) and the original population phenotypic value (X₀),
R = X₀ - X₁
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Now that we know these concepts and how to calculate them, we can solve the proposed problem.
<u>Available data: </u>
- trying to decrease the maturation time in a population of sunflowers.
- the population mean time to flower is 100 days → X₀
- Chosen parental Plants mean flowering time is 90 days → Xs
- the narrow-sense heritability for flowering time is 0.2 → h²
According to what we sow previously, we need to find out the value of X₁, which reflects the next generation average time to flowering.
- We know that R = X₁ - X₀, so we need to clear this formula to calculate X₁
X₁ = R + X₀
We already know that X₀ = 100 days,
Now we need to calculate R.
We know that h² = 0.2,
Now we need to calculate SD
Xs = 90 days → Parentals media flowering time
X₀ = 100 → Population media flowering time
SD = Xs - X₀
SD = 90 - 100
SD = - 10 days
Knowing this, we can calculate R
o h² = 0.2
o SD = - 10
R = 0.2 x (-10)
R = - 2
- Finally, once we know the R-value we can calculate the X₁ value
X₁ = R + X₀
X₁ = - 2 + 100
X₁ = 98
Answer:
D, Cholera and Dysentery
Explanation:
Colds travel through contact and air. Tetanus infects through metal.
<span>Connective tissue supports the framework of the liver, and epithelial tissue protects the liver.
Connective tissue holds the liver in place during movement, and epithelial tissue forms the lining of the liver.
Connective tissues are mainly used in forming support networks within tissues and Epithelial tissue tend to line the organs and form protective cell layers.</span>
By using both of these schemes, energy source and locomotion, amoeboids can be classified properly. Both schemes play an important part of amoeboid’s taxonomy classification because these organisms changes its shape when feeding. Amoebas are traditionally classified under sub-phylum Sarcodina, single-celled with pseudopods (use for locomotion) but recent studies show that they are not monophyletic and actually belong to other groups of organisms — with locomotion and source of nutrients as basis.
Answer:
A: can be subject to environmental conditions.
Explanation:
Phenotype is a genetics term used to describe an individual's observable characteristics that result from interactions with the genotype and nonheritable environmental factors.
Phenotypes are the <u>manifested</u> <u>aspects</u> of the morphology, physiology, biochemical properties, behavior and ecological relationships of an organism.
Given these statements, it can be concluded that two organisms cannot have the same phenotype (not even twins), because there will always be, however small, a morphological or physiological difference between them.
