Answer:
Step-by-step explanation:
Since this is a system with two equations, we can easily use a graphing calculator to find the solution
The intersection between the graphs of the equations
y = 3x + 10
2y = 6x – 4 (if we divide by two)
y = 3x - 2
However, we can see that the graphs have the same slope m = 3
Since both equations are not equal, there is no solution for this system
Please see attached graph. The lines are parallel and they never touch each other.
Answer:
C 10 in
Step-by-step explanation:
side of P is
= 6
side of Q is
= 8
for missing side use Pythagorean theorem
= ![6^{2} + 8^{2}](https://tex.z-dn.net/?f=6%5E%7B2%7D%20%20%2B%208%5E%7B2%7D)
r^{2} = 36 + 64
r^{2} = 100
r = 10 in
Answer: eww no
Step-by-step explanation:
Answer:
No I do not agree with Andre says that 3 divided by 2/3 Solving for 3 ÷ 2/3
3 ÷ 2/3
= 3 × 3/2
= 9/2
= 4 1/2
Therefore, 3 divided by 2/3 is 4 1/2
Andre's reasoning is wrong.
Step-by-step explanation:
It is incorrect
Let's divide and compare the sum
3 : 2/3 = 3*3/2 = 9/2 = 4 1/2
and
There are four 2/3 fractions and one 1/3 fraction
The 1/3 fraction is 1/2 of 2/3 fraction so instead of counting 1/3 as 1/3 it should be counted as 1/2
Answer:2 in.
Step-by-step explanation:
Given
Dimension of photo frame is ![20\ in.\times 24\ in.](https://tex.z-dn.net/?f=20%5C%20in.%5Ctimes%2024%5C%20in.)
If the photo cover an area of ![320\ in.^2](https://tex.z-dn.net/?f=320%5C%20in.%5E2)
Suppose x be the width of border
Therefore dimension of frame without border is
![A'=(20-2x)(24-2x)](https://tex.z-dn.net/?f=A%27%3D%2820-2x%29%2824-2x%29)
And
must be equal to ![320\ in.^2](https://tex.z-dn.net/?f=320%5C%20in.%5E2)
So,
![\Rightarrow (20-2x)(24-2x)=320](https://tex.z-dn.net/?f=%5CRightarrow%20%2820-2x%29%2824-2x%29%3D320)
![\Rightarrow (10-x)(12-x)=80](https://tex.z-dn.net/?f=%5CRightarrow%20%2810-x%29%2812-x%29%3D80)
![\Rightarrow 120-10x-12x+x^2=80](https://tex.z-dn.net/?f=%5CRightarrow%20120-10x-12x%2Bx%5E2%3D80)
![\Rightarrow x^2-22x+40=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E2-22x%2B40%3D0)
![\Rightarrow x^2-20x-2x+40=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E2-20x-2x%2B40%3D0)
![\Rightarrow (x-2)(x-20)=0](https://tex.z-dn.net/?f=%5CRightarrow%20%28x-2%29%28x-20%29%3D0)
Thus there are two values of x out of which
is not valid because it is not feasible
thus width of border is ![x=2\ in.](https://tex.z-dn.net/?f=x%3D2%5C%20in.)