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LenKa [72]
3 years ago
14

Chicxulub is a crater on the Yucatán Peninsula of Mexico. It was formed 6.5 × 107 years ago. Vredefort crater in South Africa wa

s formed approximately 2 × 109 years ago. Sudbury Basin in Canada is a crater that formed approximately 1.8 × 109 years ago. Acraman crater in Australia was formed 5.8 × 108 years ago. Which crater is the oldest?
Mathematics
2 answers:
Rus_ich [418]3 years ago
5 0

Answer: The oldest one is Vredfort Crater.

Step-by-step explanation:

The data is:

Chicxulub was formed 6.5x10^7 years ago.

Vredfort was formed 2x10^9 years ago.

Sudbury basin was formed 1.8x10^9 years ago.

Acraman crater was formed 5.8x10^8 years ago.

We want to find the oldest, so we need to find the larger number of the 4 we have.

For this, we need to see at the exponents, the larger the exponent the larger the number.

We have two with a 9 in the exponent:

Vredfort and Sudbury.

Now we look at the number, Vredfort has 2x10^9 and Sudbury has 1.8x10^9.

Both have the same exponent, but the scalar of Vredfort is larger (2 is greater than 1.8) so we have that Vredfort is older.

polet [3.4K]3 years ago
4 0

Answer: Vredefort

Step-by-step explanation: Vredefort is 2 billion years old unlike Chicxulub crater which is only 65 million years old.

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72 pies

Step-by-step explanation:

24 pies + 48 pies = 72 pies

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Find the area of the shaded region y = x 2 - 4x + 3
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8.) A line passes through the points (k, 4) and (3, -6). The line is perpendicular to
amm1812

Answer:

K = 43

Step-by-step explanation:

We'll begin by determining the gradient of the equation 5y + 4x = 8. This can be obtained as follow:

5y + 4x = 8

Rearrange

5y = 8 – 4x

5y = –4x + 8

Comparing 5y = –4x + 8 with y = mx + c, the gradient m is –4

Next, we shall determine the gradient of the line perpendicular to the line with equation 5y = 8 – 4x.

This can be obtained as follow:

For perpendicular lines, their gradient is given by:

m1 × m2 = – 1

With the above formula, we can obtain the gradient of the line as follow:

m1 × m2 = – 1

m1 = –4

–4 × m2 = – 1

Divide both side by –4

m2 = –1/–4

m2 = 1/4

Finally, we shall determine the value of k as follow:

Coordinate => (k, 4) and (3, –6)

x1 coordinate = k

y1 coordinate = 4

x2 coordinate = 3

y2 coordinate = –6

Gradient (m) = 1/4

m = (y2 – y1) / (x2 – x1)

1/4 = (–6 – 4) / (3 – K)

1/4 = –10 /(3 – K)

Cross multiply

3 – K = 4 × –10

3 – K = –40

Collect like terms

– K = – 40 –3

–k = –43

Divide both side by – 1

K = –43/–1

k = 43

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