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2 years ago

Violation of grammatical rules in poem Grandmother means

Mathematics

1 answer:

Sergeu [11.5K]2 years ago

7 0

Answer:

fcvbghjuiolkjuytrdfgyuiolkjuhytrfghuiol,kjhgtfrghjk

Step-by-step explanation:

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Mr. King has 36 pair of shoes. 3/4 of them are gym shoes, how many of his shoes are gym shoes

Alex777 [14]

Answer:

The number of pair of gym shoes does Mr. king has is 27 pairs .

Step-by-step explanation:

Given as :

Total number of pairs of shoes does king has = 36 pairs

The number of gym shoes = $\dfrac{3}{4}$ of the total pairs of shoes

Let The number of pair of gym shoes = n

<u>According to question</u>

The number of gym shoes = $\dfrac{3}{4}$ × the total pairs of shoes

Or, n = $\dfrac{3}{4}$ × 36

i.e n = $\frac{3\times 36}{4}$

Or, n = 3 × 9

∴ n = 27

So, The number of pair of gym shoes = n = 27 pairs

Hence, The number of pair of gym shoes does Mr. king has is 27 pairs . Answer

6 0

3 years ago

Find , , and if and terminates in quadrant .

ioda

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

STEP - BY - STEP EXPLANATION

What to find?

• sin2x

• cos2x

• tan2x

Given:

tanx = 2/3 = opposite / adjacent

We need to first make a sketch of the given problem.

Let h be the hypotenuse.

We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.

Using the Pythagoras theorem;

hypotenuse² = opposite² + adjacent²

h² = 2² + 3²

h² = 4 + 9

h² =13

Take the square root of both-side of the equation.

h =√13

This implies that hypotenuse = √13

We can now proceed to find the values of ainx and cosx.

Using the trigonometric ratio;

$\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}$ $\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}$

And we know that tanx =2/3

From the trigonometric identity;

sin 2x = 2sinxcosx

Substitute the value of sinx , cosx and then simplify.

$\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})$ $=\frac{12}{13}$

Hence, sin2x = 12/13

cos2x = cos²x - sin²x

Substitute the value of cosx, sinx and simplify.

$\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\ \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}$

Hence, cos2x = 5/13

tan2x = 2tanx / 1- tan²x

$\tan 2x=\frac{2\tan x}{1-\tan ^2x}$ $=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}$ $=\frac{\frac{4}{3}}{1-\frac{4}{9}}$ $=\frac{\frac{4}{3}}{\frac{9-4}{9}}$ $=\frac{\frac{4}{3}}{\frac{5}{9}}$ $=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}$