Answer:
<u>As per the graph we see:</u>
Domain is:
Range is:
Answer:
275 m^3
Step-by-step explanation:
The volume of a triangular pyramid is V=(1/3)Ah, where A is the area of the triangular base and h is the height.
First, let's find A, the area of the base. The area of a triangle is bh/2, where b is the base and h is the height.
In this question, 5 is the base and 15 is the height, so A=5*15/2=75/2.
Now we know A is 75/2, so let's go back to the formula for the volume of a pyramid. We are given h is 22, so
V=(1/3)(75/2)*22=275
We can set up a system of equations to solve this.
120b + 90d = 270
60b + 110d = 265
To cancel out b, first make the b terms equal.
60b · 2 + 110d · 2 = 265 · 2
120b + 220d = 530
Now subtract the equations.
120b + 90d = 270
-120b + 220d = 530
---------------------------
-130d = -260
Solve for d.
-130d/-130 = -260/-130
d = 2
Now put the value of d in one of the equations.
60b + 110d = 265
60b + 110 · 2 = 265
60b + 220 = 265
60b + 220 - 220 = 265 - 220
60b = 45
60b/60 = 45/60
b = 0.75
Each candy bar sells for $0.75
Hope this helps! :)
A) 2(1+2c)
2+4c = 2+4c
B) 6(14r-2t)
= 84r-12t
To solve this problem you must apply the proccedure shown below:
1. You have that:
<span> - The scale model is 11 inches long and 8.5 inches wide.
- The door to her room takes up 1.75 inches.
- The longest wall in Jessica’s actual room is 15 feet long.
2. Therefore, the actual size of the door is:
15 feet=180 inches
1.75 inches(180 inches/11 inches)=28.63 inches
3. If the door in completely open, you must apply the formula for calculate the area of a semicircle:
A=</span>πr²/2
r=28.63 inches
A=π(28.63 inches)²/2
A=1288.11 inches²
The answer is: 1288.11 inches²
