Maximize Q = xy^2, where x and y are positive numbers, such that x + y^2 = 4.
1 answer:
Hello,
x+y²=4==>y²=4-x
Max(Q=xy²)=Max(Q=x(4-x))=Max(Q=4x-x²)
Q'(x)=4-2x =0
==>x=4/2=2 ==>y²=4-2=2==>y=√2 since y>0
Q''(x)=-2==>a maximum.
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