All categories

3 years ago

De cuantas formas distintas se puede formar una fila de 10 personas?

Mathematics

1 answer:

Rashid [163]3 years ago

6 0

Answer:

Do you mean by standing together?

Step-by-step explanation:

You might be interested in

Brenda’s scores on the first three of four 100-point science tests were 95, 92, and 89. What score does she need on her fourth s

attashe74 [19]

Average of 93

4 scores
(95+92+89+x)/4<u>></u>93
times 4 both sides
276+x<u>></u>372
minus 276 both sides
x<u>></u>96

A

6 0

3 years ago

Read 2 more answers

Write an expression that represents the quotient of 24 and 3 plus x

steposvetlana [31]

Answer:

( 24 / 3 ) + x

Step-by-step explanation:

the expression would be ( 24 / 3 ) + x

4 0

3 years ago

A 5-meter ladder is leaning against the side of a house. The foot of the ladder is pulled away from the house at a rate of 0.4 m

Flura [38]

<h2>The top of the ladder is descending at 0.3 m/s.</h2>

Step-by-step explanation:

By Pythagoras theorem we know that

Hypotenuse² = Base² + Perpendicular²

h² = b² + p²

We have for ladder

h = 5 m

b = 3 m

5² = 3² + p²

p = 4 m

$\frac{db}{dt}=0.4m/s\\\\\frac{dh}{dt}=0$

Differentiating h² = b² + p² with respect to time

$2h\times \frac{dh}{dt}=2b\times \frac{db}{dt}+2p\times \frac{dp}{dt}\\\\5\times 0=3\times 0.4+4\times \frac{dp}{dt}\\\\\frac{dp}{dt}=-0.3m/s$

The top of the ladder is descending at 0.3 m/s.

3 0

3 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

3 years ago

Write in expanded form. Useto indicate multiplication. 5 2

nata0808 [166]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers