Can someone help me plz on this. I don't understand
1 answer:
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Use the image below for your answer please
Formula of the Volume of a hemisphere:
V =
r³
144
= r³
Multiply by 3 to cancel fraction in the right side
144 × 3 = 2 r³
432 = 2r³
Divide by 2 on either sides to isolate r³
= 
r³
2 and 
cancel out
216 = r³
Take cube root to find the radius
![\sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%7D%20)
= ![\sqrt[3]{r^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Br%5E3%7D%20)
6 = r
Radius is 6 units
The formula of the surface area of a hemisphere is:
S.A = 2r² + r²
=
(6)² + (6)²
=2 × 36 + 36
= 72 + 36
= 108 units² (in terms of )
≈ 339.12 units²
Surface area = 108 units
V =
144
Multiply by 3 to cancel fraction in the right side
144
432
Divide by 2
2
216 = r³
Take cube root to find the radius
6 = r
Radius is 6 units
The formula of the surface area of a hemisphere is:
S.A = 2
=
=2
= 72
= 108
≈ 339.12 units²
Surface area = 108
Answer:
(A) n(Eᶜ)=40
Step-by-step explanation:
The Sample Space for is given as:
(1,2),(1,3),(1,4),(1,5),(1,6),(1,7),(1,8),(1,9),(1,10),(1,11)
(2,3),(2,4),(2,5),(2,6),(2,7),(2,8),(2,9),(2,10),(2,11)
(3,4),(3,5),(3,6),(3,7),(3,8),(3,9),(3,10),(3,11)
(4,5),(4,6),(4,7),(4,8),(4,9),(4,10),(4,11)
(5,6),(5,7),(5,8),(5,9),(5,10),(5,11)
(6,7),(6,8),(6,9),(6,10),(6,11)
(7,8),(7,9),(7,10),(7,11)
(8,9),(8,10),(8,11)
(9,10),(9,11)
(10,11)
n(S)=55
Event E is the Event that the two numbers are odd.
Therefore: Complement of E will be the event that any of the two numbers is even.
The Sample Space of the complement of E is:
Therefore:
n(Eᶜ)=40