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alexdok [17]
3 years ago
10

SOMEONE PLEASE HELP ME ASAP PLEASE PLEASE PLEASE !!!!​

Mathematics
1 answer:
Gemiola [76]3 years ago
4 0

Answer:

Step-by-step explanation:

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4 years ago
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lianna [129]

Answer:

I got the answer 13

Step-by-step explanation:

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3 years ago
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A recent survey of 252 customers, selected at random from a database with 12,861 customers, found that 208 are satisfied with th
inysia [295]

Answer:

The upper bound of a 99% confidence interval for the percentage satisfied for all customers in the database is 88.70%.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Sample of 252 customers, 208 are satisfied:

This means that n = 252, \pi = \frac{208}{252} = 0.8254

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8254 + 2.575\sqrt{\frac{0.8254*0.1746}{252}} = 0.8870

As a percentage:

100%*0.8870 = 88.70%

The upper bound of a 99% confidence interval for the percentage satisfied for all customers in the database is 88.70%.

8 0
3 years ago
Antonio’s weekly allowance is given by the equation A=0.5c+10, where c is the number of chores he does. If he received $16 in al
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A=0.5(12)+10= 16. Antonio has 12 chores.
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3 years ago
What is the common denominator of
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Probably x+2 good luck
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4 years ago
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