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SIZIF [17.4K]
3 years ago
7

I need help right away with the next problem.

Mathematics
1 answer:
Anna71 [15]3 years ago
5 0

Answer:

  see below

Step-by-step explanation:

To convert the numbers to percentages, divide each number by the table total (80) and multiply by 100%. That is equivalent to multiplying each number by 1.25%. For example, 18·1.25% = 22.5% (middle table number).

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Someone answer this random question
gayaneshka [121]

Answer:

hmmmmm... thats a tough one

its probably ur mom

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
If ln(4x+y)=2x-3,then dy/dx=
Viktor [21]

\ln(4x+y)=2x-3

Differentiate both sides wrt x:

\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}

By the chain rule, we get

\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2

\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2

Solve for \frac{\mathrm dy}{\mathrm dx}:

4+\dfrac{\mathrm dy}{\mathrm dx}=8x+2y

\boxed{\dfrac{\mathrm dy}{\mathrm dx}=8x+2y-4}

4 0
3 years ago
John can mow a lawn in 80 minutes. Rocky can mow the same lawn in 120 minutes. How long does it take for both John and Rocky to
mario62 [17]

Answer: it will take them 48 minutes.

Step-by-step explanation:

John can mow a lawn in 80 minutes. This means that the rate at which he moans the lawn per minute is 1/80

Rocky can mow the same lawn in 120 minutes. This means that the rate at which Rocky can mow the same lawn per minute is 1/120

If they work together, they would work simultaneously and their individual rates are additive. This means that their combined working rate would be

1/80 + 1/120 = 200/9600 = 1/48

Assuming it takes t hours for both of them to clean the room working together, the working rate per hour would be 1/t. Therefore,

1/48 = 1/t

t = 48 minutes

4 0
3 years ago
Multiply out and simplify to obtain a minimum sum-of-products boolean expression:
max2010maxim [7]

Answer:

As per the question, we need to convert product of sum into sum of product,

Given:

(A' +B+C')(A'+C'+D)(B'+D'),

At first, we will solve to parenthesis,

= (A'+C'+BD) (B'+D')

As per the Rule, (A+B)(A+C) = A+BC, In our case if we assume X = A'+C', then,

(A' +B+C')(A'+C'+D) = (A'+C'+B)(A'+C'+D) = (A'+C'+BD)

Now,  

= (A'+C'+BD) (B'+D') = A'B' + A'D' + C'B' +C'D' +BDB' +BDD"

As we know that AA' =  0, it mean

=A'B'+A'D'+C'B'+C'D'+D*0+B0

=A'B'+A'D'+C'B'+C'D'               as B * 0 and D*0 = 0

Finally, minimum sum of product boolean expression is

A''B'+A'D'+C'B'+C'D'

=

5 0
3 years ago
Need help solving this differentiation problem please. Thank you.
DIA [1.3K]
First convert the terms to fractional exponents

u  =  t^2/3  - 3t^3/2

differentiating

u'  =  2/3 t^ (2/3 - 1) - 3* 3/2  t^(3/2 - 1)

     =  2/3 t ^(-1/3) - 9/2 t ^(1/2)

     =  2 / (3∛t) -  9 √ t / 2   in radical form


7 0
3 years ago
Read 2 more answers
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