Which of the following correctly describes the sum below?

What is the greatest common factor of 9, 36, and 18

zalisa [80]

Answer:

9.

Step-by-step explanation:

6 0

2 years ago

Gretchen has a set of blocks of heights 1, 2, and 4-centimeters. Imagine stacking the blocks one on top of the other to make a t

notsponge [240]

Answer:

$t_{n}$ = $t_{n-1}$ + $t_{n-2}$ + $t_{n-4}$

Step-by-step explanation:

$t_{n}$ =multiple ways to climb a tower

When n = 1,

tower= 1 cm

$t_{1}$ = 1

When n = 2,

tower =2 cm

$t_{2}$ = 2

When n = 3,

tower = 3 cm

it can be build if we use three 1 cm blocks

$t_{3}$ = 3

When n = 4,

tower= 4 cm

it can be build if we use four 1 cm blocks

$t_{4}$ = 6

When n > 5

tower height > 4 cm

so we can use 1 cm, 2 cm and 4 cm blocks

so in that case if our last move is 1 cm block then $t_{n-1}$ will be

n —1 cm

if our last move is 2 cm block then $t_{n-2}$ will be

n —2 cm

if our last move is 4 cm block then $t_{n-4}$ will be

n —4 cm

$t_{n}$ = $t_{n-1}$ + $t_{n-2}$ + $t_{n-4}$

4 0

3 years ago

Read 2 more answers

Simplify 8(3+5) Help me please

amid [387]

Answer:

64

Step-by-step explanation:

pemdas says parenthesis first

3+5=8

8(8)

8 times 8 equals 64

3 0

3 years ago

Read 2 more answers

Plz help..................

Sever21 [200]

20mn - 30m
As you can see, both numbers are divisible by 10m. So if you were to divide them both, you would be left with, 10m (2n - 3), which would be the correct answer.

7 0

3 years ago

The first term of a geometric sequence is 6 and the fourth term is 384. What is the sum of the first 10 terms of the correspondi

aleksandrvk [35]

Answer:

2097150

Step-by-step explanation:

GIVEN :-

First term of G.P. = 6
Forth term of G.P. = 384

TO FIND :-

Sum of first 10 terms of the G.P.

CONCEPT TO BE USED IN THIS QUESTION :-

Geometric Progression :-

It's a sequence in which the successive terms have same ratio.

General form of a G.P. ⇒ a , ar , ar² , ar³ , ....... [where a = first term ; r = common ratio between successive terms]

Sum of 'n' terms of a G.P. ⇒ $\frac{a(r^n - 1)}{r-1}$ .

[NOTE :- $\frac{a(1-r^n)}{1-r}$ can also be the formula for "Sum of n terms of G.P." because if you put 'r' there (assuming r > 0) you'll get negative value in both the numerator & denominator from which the negative sign will get cancelled from the numerator & denominator. YOU'LL BE GETTING THE SAME VALUE FROM BOTH THE FORMULAES.]