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kondor19780726 [428]
2 years ago
13

In the Lincoln Grade School, 200 students are in the first grade, 150 are in the second grade, 300 in the third grade, 250 in th

e fourth grade, 200 in the fifth grade, and 275 in the sixth grade. Construct a bar graph that represents the number of students per grade at Lincoln Grade School. Label the bar graph with a title and the correct, consistent scale.
Mathematics
1 answer:
maxonik [38]2 years ago
8 0

Answer:

In image

Step-by-step explanation:

-------------------

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Question 7 of 10
Ipatiy [6.2K]

Answer:

A (point) is the answer to the question.

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3 years ago
What is the surface area of this shape?<br> 1 cm<br> 5 cm<br> 4 cm<br> 2 cm<br> 6 cm<br> 3 cm
a_sh-v [17]

Answer:

88 cm²

Step-by-step explanation:

Each square is 1 cm². Count the squares of each face and add them.

Front face (purple): 14 cm²

Back face (hidden): 14 cm²

Right lower face (orange): 6 cm²

Right upper face (orange): 6 cm²

Left face (hidden): 12 cm²

Upper top face (blue): 3 cm²

Lower top face (blue): 15 cm²

Bottom face (hidden): 18 cm²

Add all areas above:

88 cm²

7 0
2 years ago
GARDENING A gardener uses a grow light to grow vegetables indoors. If m∠1=(8x)° and m∠2=(7x−4)°, what is m∠1?
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Give me a like bshshejsjaejke
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kotegsom [21]

Answer:

C

Step-by-step explanation:

5 0
2 years ago
A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
2 years ago
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