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Likurg_2 [28]
3 years ago
11

Part b : how much money will be in biancas account after 5 years ?

Mathematics
1 answer:
pantera1 [17]3 years ago
4 0

MYYYYY nUUUUUUUUUUUUUUUUUUT

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What does 312,819 round to, to the nearest ten thousand?
Paha777 [63]

Answer:

310,000

Step-by-step explanation:

3 0
3 years ago
Help with integer solutions to inequalities
skad [1K]
X1 + X2 + X3 <27 for all Xi> 0
X1 + X2 + X3 <27 for all Xi> 0, X2 >/ 5
6 0
3 years ago
If a rectangle's length is y−2 and the width is 3y+2 write an expression for the perimeter and an expression for the area.
aalyn [17]

Answer:

Area = 3y^2 - 4y - 4 units square.

Perimeter = 8y units.

Step-by-step explanation:

Area of a rectangle = length * width.

Perimeter of a rectangle = 2*(length + width).

It is given that length = y−2 units and width = 3y+2 units. To find the area and the area of the rectangle in terms of y, simply put the length and the width in the above area and perimeter equations.

Area = length * width = (y-2)*(3y+2).

Expanding the expression gives:

Area = 3y^2 + 2y - 6y - 4 = (3y^2 -4y - 4) units square.

Similarly,

Perimeter = 2*(length + width) = 2*(y-2 + 3y+2) = 2*4y = 8y units.

Therefore, the expression for the area and the perimeter of the given rectangle is (3y^2 - 4y - 4) units square and (8y) units respectively!!!

3 0
4 years ago
The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we
Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

            Sigma, σ = 0.200 kg

            Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

$H_0 : \mu = 13 $

$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

 Test statics :

   $Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}} $

  $Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}} $

          $=\frac{1.82}{0.04}$

          = 45.5  

P-value = 2 x P(Z > 45.5)

            = 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value  < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0
3 years ago
Arthur is cutting construction paper into rectangles for a project. He needs to cut one rectangle that is 16 inches × 12 1 4 inc
kodGreya [7K]

Answer:

303.63 sq inches

Step-by-step explanation:

We need to find the area of the two rectangles he cuts and add them together.

The area of a rectangle is given as:

A = L * B

The first rectangle is 16 inches × 12 1/4 inches. Its area is:

A = 16 * 12 1/4 = 16 * 49/4 = 196 sq inches

The second rectangle is 10 1/2 inches by 10 1/4 inches. Its area is:

A = 10 1/2 * 10 1/4 = 21/2 * 41/4 = 107.63 sq inches

The total square inches of construction paper that he needs is:

196 + 107.63 = 303.63 sq inches

4 0
3 years ago
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