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Oksana_A [137]
3 years ago
8

Duncan rode 2 kilometers on his bike.Harold rode twice as far as Duncan and Sara combined. How many kilometers did the three fri

ends ride on their bikes all together? ( 1 kilometer=1000 meters)A.5km B.10km C.30km D.15 km
Mathematics
1 answer:
xz_007 [3.2K]3 years ago
6 0

Answer:

Total distance covered by all three friends is,

15 km assuming that Sara traveled a distance of 3 km.

30 km assuming that Sara traveled a distance of 8 km.

Step-by-step explanation:

Let D denotes the distance that Duncan covered on his bike.

Let H denotes the distance that Harold covered on his bike.

Let S denotes the distance that Sara covered on her bike.

Duncan rode 2 kilometers on his bike.

Mathematically,

D = 2 km

Harold rode twice as far as Duncan and Sara combined.

Mathematically,

H = 2(D + S)

H = 2(2 + S)

H = 4 + 2S

The distance covered by three friends all together is  

D + H + S

We don’t have enough information at this point to find out the total distance covered by all of them, so we need to assume the distance covered by Sara.

Assuming that Sara covered 0 km then

H = 4 + 2(0)

H = 4

Then total distance is

D + H + S

2 + 4 + 0

6 km

But 6 km doesn’t match any given option so try assuming another value for the distance covered by Sara.

Assuming that Sara covered 2 km then

H = 4 + 2(2)

H = 8

Then total distance is

D + H + S

2 + 8 + 2

12 km

But 12 km doesn’t match any given option so try assuming another value for the distance covered by Sara.

Assuming that Sara covered 3 km then

H = 4 + 2(3)

H = 10

Then total distance is

D + H + S

2 + 10 + 3

15 km

Assuming that Sara covered 8 km then

H = 4 + 2(8)

H = 20

Then total distance is

D + H + S

2 + 20 + 8

30 km

Therefore, the total distance covered by all three friends is,

15 km assuming that Sara traveled a distance of 3 km.

30 km assuming that Sara traveled a distance of 8 km.

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Samantha has a shelf that is 95 over 4 inches wide. How many books can Samantha arrange on the shelf if each book is 5 over 4 in
love history [14]

Answer:

Option 1 - 19, because the number of books is 95 over 4 divided by 5 over 4

Step-by-step explanation:

Given : Samantha has a shelf that is 95 over 4 inches wide.

To find : How many books can Samantha arrange on the shelf if each book is 5 over 4 inches thick?

Solution :

The thickness of shelf = \frac{95}{4} inches

Each book thickness = \frac{5}{4} inches

Let the total number of books that could be arranged in the shelf be 'n'.

\text{Number\ of\ books\ arranged}=\dfrac{\text{Thickness\ of\ shelf}}{\text{Thickness\ of\ one\ book}}

Substitute the values,

n=\dfrac{\dfrac{95}{4}}{\dfrac{5}{4}}

n=\dfrac{95\times 4}{5\times 4}

n=\dfrac{95}{5}

n=19

Therefore, option 1 is correct.

19, because the number of books is 95 over 4 divided by 5 over 4

4 0
3 years ago
Deshaun started baking at 9:25 AM and finished at 10:41 AM How long did it take him? Give your answer in hours and minutes​
Zepler [3.9K]

Answer:

1 hour and 16 minutes

Step-by-step explanation:

you just have to count up from 9:25 to 10:41 and translate the amount of minutes you counted into hours

7 0
2 years ago
If 2x+20 and 3x+20 makes a straight angke find value of x​
erma4kov [3.2K]

Answer:

x = 28

Step-by-step explanation:

The sum of the angles in a straight angle = 180°

Sum the angles and equate to 180

2x + 20 + 3x + 20 = 180

5x + 40 = 180 ( subtract 40 from both sides )

5x = 140 ( divide both sides by 5 )

x = 28

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3 years ago
PLEASE HELP ME PLEASE??
BigorU [14]

Answer:

Table A is correct

Step-by-step explanation:

All you have to do is multiply the hours by 5 to get the answer.

Table B is adding not multiplying.

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4 0
3 years ago
Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1
belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

            F(x) = \int\limits^a_b {f(x)} \, dx

By using integration formula

\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

 \int\limits^6_^-6} (x^{5}  + 8 x^{4}  + 2 x^{2}  + 5 x + 15) )dx

<em>On integration , we get</em>

=   (\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}

F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)

= (\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))

After simplification and cancellation we get

 =  \frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6

on calculation , we get

= \frac{124,416}{5} + \frac{864}{3} + 180

On L.C.M  15

= \frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0
3 years ago
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