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tensa zangetsu [6.8K]
4 years ago
11

James cut out four parallelograms, the dimensions of which are shown below. Parallelogram 1 length: 12 in. width: 15 in. diagona

l: 20 in. Parallelogram 2 length: 16 in. width: 30 in. diagonal: 34 in. Parallelogram 3 length: 20 in. width: 21 in. diagonal: 29 in. Parallelogram 4 length: 18 in. width: 20 in. diagonal: 26 in. James put the parallelograms together so one vertex from each paper exists on a point, as shown in the circle. mr025-1.jpg Which statement explains whether or not the parallelgrams can be put together so each occupies one-quarter of the area of the circle without overlapping any other pieces? Check all that apply. The quadrilaterals can be placed such that each occupies one-quarter of the circle. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 2 do not form right angles. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 3 do not form right angles. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.
Mathematics
2 answers:
mr_godi [17]4 years ago
8 0
Quarter of the circle because the vertices of parallelogram 3 do not form right angles. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices
Alchen [17]4 years ago
4 0

Answer:

B. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles.

E. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.

Step-by-step explanation:

P1: 12^2+15^2=20^2  144+225=400  369=400

P2: 16^2+30^2=34^2  256+900=1156  1156=1156

P3: 20^2+21^2=29^2  400+441=841  841=841

P4: 18^2+20^2=26^2  324+400=676  724=676

So the answers are B and E

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IrinaVladis [17]

Answer:

(-6,-4)

Step-by-step explanation:

to get to -4 from 2 you have to subtract 6, making the slope x/6 but you said the slope is 3/2. divide 6 by 2 and you get 3. 3x3=9 making the slope 9/6. simplify and you get 3/2

4 0
3 years ago
What is the length of segment TR with T(-4,5) and R(2, -1)​
Brilliant_brown [7]

Answer:

The length of segment TR with T(-4,5) and R(2, -1)​ is 8.49

Step-by-step explanation:

We need to find the length of segment TR with T(-4,5) and R(2, -1)​

The length of segment can be found using distance formula.

The distance formula is: Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Putting values and finding length

We have: x_1=-4, y_1=5, x_2=2, y_2=-1

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance = \sqrt{(2-(-4))^2+(-1-5)^2}\\Distance = \sqrt{(2+4)^2+(-1-5)^2}\\Distance = \sqrt{(6)^2+(-6)^2}\\Distance = \sqrt{36+36}\\Distance = \sqrt{72}\\Distance=8.49

We found Distance = 8.49

So, The length of segment TR with T(-4,5) and R(2, -1)​ is 8.49.

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Step-by-step explanation:

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Answer:

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Digit in the ones place: 5

Step-by-step explanation:

Note the number in the place values for: 3625

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Answer:

50 J

Step-by-step explanation:

According to energy conservative law energy can not be destroyed. So as the potential energy has been decreased to 50 J, the decreased amount has become kinetic energy.

100 - 50 = 50

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