The options aren't given, however, the range of amount spent could be calculated
Answer:
Kindly check explanation
Step-by-step explanation:
Paula purchase 3 dvd and 7 cds and spent between 90 and 100. Each dvd costs the same amount the price of cd is 10 select all amounts that could be the price of the dvd
Given that :
DVD costs the same amount
Number of DVD's = 3
Cost of cds = 10
Number of cds = 7
Total cost of cd's = 10 * 7 = 70
Let the price of DVD = x
Total amount spent = 90 - 100
Lowest price of DVD :
(amount spent - price of cd) / number of dvd
(90 - 70) / 3 = 20 /3 = 6.667
Highest price :
(100 - 70) / 3 = 30 / 3 = 10
Hence the pice of each DVD will range between /
6.6666 and 10.
Hence, prices listed within the range above are possible.
Answer:
<em>No, he should have set the sum of ∠AED and ∠DEC equal to 180°, rather then setting ∠AED and ∠DEC equal to each other</em>
Step-by-step explanation:
Find the diagram attached
If line AC and BD intersects, then m<AED + m<DEC = 180 (sum of angle on a straight line is 180 degrees)
Given
m<AED = 16x+8
m<DEC = 76 degrees
16x + 8 + 76 = 180
16x + 84 = 180
16x = 180-84
16x = 96
x = 96/16
x = 6
Hence the value of x is 6
Hence the correct option is <em>No, he should have set the sum of ∠AED and ∠DEC equal to 180°, rather then setting ∠AED and ∠DEC equal to each other</em>
Answer:
8/125 ft
Step-by-step explanation:2/5 x 2/5 x 2/5 = 8/125
Answer:
The answer is point C
Step-by-step explanation:
Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
