Answer:
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Step-by-step explanation:
the answer is 0
Answer:
The mixtures are not proportional.
3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture.
its =3
Step-by-step explanation:
The one mixture contains 6 fluid ounces and 10 fluid ounces of water and vinegar respectively.
Therefore, the ratio of water to vinegar in the first mixture is 6 : 10 = 3 : 5
Now, a second mixture contains 9 fluid ounces of water and 12 fluid ounces of vinegar.
Hence, the ratio of water to vinegar in the second mixture is 9 : 12 = 3 : 4
Therefore, the mixtures are not proportional.
Therefore, we have to add x fluid ounces of vinegar to the second mixture to make it in the ratio of 3 : 5.
So,
⇒ 12 + x = 15
⇒ x = 3 fluid ounces.
Therefore, 3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture. (Answer
You don’t have any attachment so I’m sorry I cannot answer
X^2 + 5x = -2
x^2 + 5x + 2 = 0
x = -b (+-) sqrt (b^2 - 4ac) / 2a
a = 1, b = 5, and c = 2
x = -5 (+-) sqrt (5^2 - 4(1)(2)) / 2(1)
x = -5 (+-) sqrt (25 - 8) / 2
x = -5 (+-) sqrt (17) / 2
answer is : negative 5 plus or minus the square root of 17 divided by 2
I can't see it well sorry
