Answer:
Check button under error checking
Explanation:
Under the Tools tab there are two options:
Error checking and Optimize and defragment drive option.
clicking the check button with administrative permission under error checking option will examine the hard drive for errors.
Figure 1: An image — an array or a matrix of pixels arranged in columns and rows.
In a (8-bit) greyscale image each picture element has an assigned intensity that
ranges from 0 to 255. A grey scale image is what people normally call a black and
white image, but the name emphasizes that such an image will also include many
shades of grey.
Figure 2: Each pixel has a value from 0 (black) to 255 (white). The possible range of the pixel
values depend on the colour depth of the image, here 8 bit = 256 tones or greyscales.
A normal greyscale image has 8 bit colour depth = 256 greyscales. A “true colour”
image has 24 bit colour depth = 8 x 8 x 8 bits = 256 x 256 x 256 colours = ~16
million colours.
Answer:
See explanation below
Explanation:
Previos concepts
First Come First Serve (FCFS) "is an operating system scheduling algorithm that automatically executes queued requests and processes in order of their arrival".
Shortest job next (SJN), or the shortest job first (SJF) or shortest "is a scheduling policy that selects for execution the waiting process with the smallest execution time".
Shortest remaining time (SRF) "is a scheduling method that is a preemptive version of shortest job next scheduling'".
Round robin (RR) is an algorithm where the time parts "are assigned to each process in equal portions and in circular order, handling all processes without priority"
Solution for the problem
Assuming the dataset given on the plot attached.
Part a
For this algorithm the result would be:
Job A 0-6
Job B 6-(6+3) = 6-9
Job C 9-(9+1) = 9-10
Job D 10-(10+4) = 10-14
Part b
For this algorithm the result would be:
Job A 0-6
Job C 6-(6+1) = 6-7
Job B 7-(7+3) = 7-10
Job D 10-(10+4) = 10-14
Part c
For this algorithm the result would be:
Job A 0-1 until 14
Job B 2-(2+3) = 2-5
Job C 3-(3+2) = 3-5
Job D 9-(9+5) = 9-14
Part d
For this algorithm the result would be:
Job A 0-2 , 7-9, 12-14
Job B 2-4, 9-10
Job C 4-(4+1) = 4-5
Job D 5-7, 10-12
Answer:
the third one
Explanation:
the rest is below 28 apart from the third one which is 28 and is the most