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makkiz [27]
3 years ago
10

Rectangle J’K’L’M shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applied

on trapezoid STUV.
What will be the location of T’ in the image trapezoid S’T’U’V’?

A. (15, 2)

B. (18, 2)

C. (18, -2)

D. (15, -2)

Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0

The answer is (18, 2) this is because the original figure JKLM used the rule (x+13, y-3) sorry not sure if I put that rule in the correct order.

vredina [299]3 years ago
3 0

The <em><u>correct answer</u></em> is:

B. (18, 2)

Explanation:

The points of the pre-image JKLM are:

J(-7, -6); K(-4, -6); L(-4, -2); and M(-7, -2).

The points of image J'K'L'M' are:

J'(6, -9); K'(9, -9); L'(9, -5); and M'(6, -5).

Each point has moved horizontally 13 units and vertically -3 units; this gives us the translation <13, -3>.

Applying this to T, we have:

T'(5+13, 5-3) = (18, 2)

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=========================
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==========================
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