A) The situation represents an arithmetic sequence because the successive y-values have a common difference of 210.
F(1) = 240 +210
F(2) = 240 +2(210)
F(3) = 240+3(210)
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F(x)= 240 +210x.
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Answer:
1/60 probabiliity
Step-by-step explanation:
You have two independent events that you want to put together.
Let Pr. mean "probability"
Pr(5 from 10 cards and 2 on a dice ) = Pr(5 from 10 cards) * Pr( 2 on a dice)
Pr(5 from 10 cards and 2 on a dice ) =(1/10) * (1/6)
= 1/60
Pr(5 from 10 cards and 2 on a dice ) =0.0167
or 1.67% probability
C. multiply the second equation by two. Then add the equations
6 is your answer, hope it helped
Find two numbers with a sum of 20 and a difference of 14
Make two equations
X+Y=20
X-Y=14
Now add x since y cancels out and add 20+14 To end up with
2x=34
Now divide 2 both sides to get x alone
2x/2=34/2
X=17
Now substitute x answer to first equation and solve for y
17+y=20
Subtract 17 both sides
Y= 3
Your two numbers are
3 and 17
