20
There are 10 feet of posts on each side. That means there are 40 feet of fencing in total. If you divide that by two (to represent posts being 2 feet apart) then you get 20. There are 20 posts needed.
Answer:
Step-by-step explanation:
<u>The line has a positive slope and negative y-intercept.</u>
This is only matched by a choice C
Answer:
4m X 6m
Step-by-step explanation:
This is because if there is a 2m square in the middle, there is 8 m of usable space left along both sides of the garden.
Because the 2m square was in the middle, there is 8/2 = 4m along each width of the 4 small rectangles.
Becuase 4m is the width, there is 10 - 4 = 6m along each rectangle's length.
<h3>
Answer: -2w^2 + 25w = 25 or -2w^2 + 25w - 25 = 0</h3>
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Explanation:
Refer to the diagram below. The width is w. We have two opposite and parallel sides equal to this. The other two parallel congruent sides are L = 25-2w meters long. We start with the total amount of fencing, and then subtract off the two width values, so 25-w-w = 25-2w.
The area of the rectangle is
Area = length*width
Area = L*W
Area = (25-2w)*w
Area = 25w - 2w^2
Area = -2w^2 + 25w
Set this equal to the desired area (25 square meters) to get
-2w^2 + 25w = 25
and we can subtract 25 from both sides to get everything on one side
-2w^2 + 25w - 25 = 0
side note: The two approximate solutions of this equation are w = 1.0961 and w = 11.4039 (use the quadratic formula or a graphing calculator to find this)
Answer:
false
Step-by-step explanation:
the relationship between lengths/dimensions and areas is that areas are created by multiplying 2 dimensions.
when you quadruple (×4) the dimensions, then the areas are growing with the square of the factor (×4×4 = ×16), because the factor goes twice into the multiplication : one time for every dimension involved.
so, quadrupling the dimensions would multiply the areas by 16.
