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Paladinen [302]

3 years ago

8

I need help on this question

1 answer:

earnstyle [38]3 years ago

5 0

Answer:

I and III

Step-by-step explanation:

substitute 2 for y in each equation.

-9 + 27 = 18

-18 + 27 = 9

5(27) = 135

2(27) = 54

You might be interested in

Write a similarity statement comparing the two triangles.<br> △BDC∼△EDA<br> △BCD∼△EDA<br> △EAD∼△BDC

telo118 [61]

Answer:

A. △BDC∼△EDA

Step-by-step explanation:

<u>Corresponding angles are:</u>

∠A ≅ ∠C
∠D ≅ ∠D
∠B ≅ ∠E

Use same order of corresponding vertices in the name of triangles.

<u>Choices are:</u>

△BDC∼△EDA, correct
△BCD∼△E<u>DA</u>, incorrect should be △BCD∼△EAD
△EAD∼△B<u>DC</u>, incorrect should be △EAD∼△BCD

6 0

2 years ago

Janell has a 10 inch by 12 inch photograph. She wants to scan the photograph

Dmitry_Shevchenko [17]

<u>Complete Question:</u>

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

<u>Correct Answer:</u>

A) $(10-x)(12-x)=15$

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

<u>Step-by-step explanation:</u>

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

$length=10-x\\breadth=12-x$

According to question , Area of new image is :

⇒ $Area = \frac{1}{8}Length(breadth)$

⇒ $Area = \frac{1}{8}(10)(12)$

⇒ $Area = 15$

So the equation will be :

⇒ $(10-x)(12-x)=15$

b. Find the dimensions of the reduced image

Let's solve : $(10-x)(12-x)=15$

⇒ $120-10x-12x+x^2=15$

⇒ $120-22x+x^2=15$

⇒ $x^2-22x+105=0$

By Quadratic formula :

⇒ $x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $x = \frac{22 \pm8 }{2}$

⇒ $x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}$

⇒ $x = 15 , x =7$

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ $x =7$

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

7 0

3 years ago

Which equation is the inverse of y = 16x^2 + 1?

timama [110]

Switch y and x: x =16y^2 + 1
Solve for y: x-1=16y^2
16y =+-√(x-1)
y =+-√(x-1)/16

6 0

3 years ago

Read 2 more answers

1) (19-16), (-7,-15)

max2010maxim [7]

Answer:

your answer is -285,112

Step-by-step explanation: first you do this

$\frac{y1}{y2} \frac{x1}{x2} \\$

the numders should go like this

$\frac{-15}{-16} \frac{-7}{19}$

then you cross multiply

$-15*(19)\\-7*(-16)$

the answers to the multiplication

$-15*(19)= -285\\-7*(-16)=112$

the answer is

-285,112

4 0

3 years ago

Plz helps so i can pass

nasty-shy [4]

Answer:

C

Step-by-step explanation:

did it on edge

4 0

3 years ago