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4 years ago

How old am i if 300 reduced by 3 times my age is 219

1 answer:

7 0

Isn't it 27? Because if you went backwards 300-219 is 81 and 81 divided by 3 is 27. if you went forwards, 27 times 3 is 81 and 300 reduced by 81 is 219.

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Devon made a box with length x+1, width x+3, and height x-3. What is the volume of Devon's box as a function of x?

erica [24]

Answer:

(a)

$V=x^3+x^2-9x-9$

(b)

$x=10$

(c)

$x=\frac{7}{2}$

Step-by-step explanation:

we are given

length is x+1

$L=x+1$

width is x+3

$W=x+3$

height is x-3

$H=x-3$

(a)

we can use volume formula

$V=L\times W\times H$

now, we can plug it

$V=(x+1)\times (x+3)\times (x-3)$

now, we can simplify it

$V=x^3+x^2-9x-9$

(b)

we are given volume =1001

so, we can set V=1001

and then we can solve for x

$V=x^3+x^2-9x-9=1001$

now, we can factor it

$\left(x-10\right)\left(x^2+11x+101\right)=0$

$x-10=0$

$x=10$

(b)

we are given volume

so, we can set

$V=14\frac{5}{8}=\frac{14\times 8+5}{8}$

$V=\frac{117}{8}$

and then we can solve for x

$V=x^3+x^2-9x-9=\frac{117}{8}$

now, we can factor it

$8x^3+8x^2-72x-189=0$

$\left(2x-7\right)\left(4x^2+18x+27\right)=0$

$2x-7=0$

$x=\frac{7}{2}$

8 0

3 years ago

As the number of degrees of freedom for a t distribution increases. True or False

valkas [14]

Answer:

t distribution behaves like standard normal distribution as the number of freedom increases.

Step-by-step explanation:

The question is missing. I will give a general information on t distribution.

t-distribution is used instead of normal distribution when the sample size is small (usually smaller than 30) or population standard deviation is unknown.

Degrees of freedom is the number of values in a sample that are free to vary. As the number of degrees of freedom for a t-distribution increases, the distribution looks more like normal distribution and follows the same characteristics.

7 0

4 years ago

Find the area of the triangle with the given base and height. b = 3 m and h = 10 1/2 m

svetoff [14.1K]

Statement:

The base of a triangle is 3m and its height is $10 \frac{1}{2}$ m.

To find out:

The area of the triangle.

Solution:

Given, base = 3m, height = $10 \frac{1}{2}$ m
We know,

$\sf \: area \: \: of \: \: a \: \: triangle = \frac{1}{2} \times base \: \times height$

Therefore, the area of the triangle

$\sf = (\frac{1}{2} \times 3 \times 10 \frac{1}{2} ) {m}^{2} \\ \sf = ( \frac{1}{2} \times 3 \times \frac{21}{2} ) {m}^{2} \\ = \sf \frac{63}{4} {m}^{2} \\ = \sf 15\frac{3}{4} {m}^{2}$