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Doss [256]
3 years ago
6

A team of 17 softball players need to choose three players to refill the water cooler. How many different ways are there to sele

ct 3 players?
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
5 0
<h3>Answer: 680 different combinations</h3>

=======================================================

Explanation:

If order mattered, then we'd have 17*16*15 = 4080 different permutations. Notice how I started with 17 and counted down 1 at a a time until I had 3 slots to fill. We count down by 1 because each time we pick someone, we can't pick them again.

So we have 4080 different ways to pick 3 people if order mattered. But again order doesn't matter. All that counts is the group itself rather than the individual or how they rank. There are 3*2*1 = 6 ways to order any group of three people, which means there are 4080/6 = 680 different combinations possible.

An alternative is to use the nCr formula with n = 17 and r = 3. That formula is

_n C _r = \frac{n!}{r!*(n-r)!}

where the exclamation marks indicate factorials

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The answer is:  {4, 1} .
________________________________________________________
Explanation:
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Given the equations:
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      "12x = 54 −<span> 6y ;
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Multiply the second equation (both sides) by "-1" ;
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  -1*{-17x = -62 − 6y} ;

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17x = 62 + 6y ;
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{Note: The reason we do this is that we notice the TWO "-6y" values; and by multiplying one of the entire equations by "-1" ; we can change said equation to an equation with a "(+6y)" value; and the "(+6y)" and the "(-6y)" values cancel out to "zero" ; providing an opportunity to isolate "x"; and to solve for "x".}.
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Now, rewrite the two equations:
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       12x = 54 − 6y ;
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↔  Rewrite; and then add the two together:

       6y + 62 = 17x 
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       0  +  116 = 29x ;

↔ 29x = 116 ;

Divide EACH SIDE of the equation by "29" ; to isolate "x" on one side of the <span>equation ; and</span> to solve for "x" ;
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   29x / 29 = 116 / 29  ;
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to get:
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           x  = 4 .
______________________________________________
Now that we have the value for "x" , which is "4" ; let us plug in "4" for "x" for either of the original two equations, to solve for "y".  In fact, let us try substituing "4" for "x" ;  for BOTH of the two original equations; to see if the value is correct.
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Our original two given equations are:
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      "12x = 54 − 6y ;

     "-17x = -62 − 6y ;
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 Let us start with the first equation:
 ________________________
      " 12x = 54 − 6y " ;
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When "x = 4" ; what does "y" equal ?

Plug in "4" for "x" ; to solve for "y" ;

  12(4) = 54 − 6y ;

→ 48 = 54 − 6y ;

Subtract "54" from EACH SIDE of the equation;

→ 48 − 54 = 54 − 6y − 54 ;

to get:

→  -6 = -6y ; 

→ Divide EACH side of the equation by "-6" ; to isolate "y" on one side of the <span>equation ; and</span> to solve for "y" ; 

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______________________________________________
Let us check to see, if the second (orginal equation) holds true when "x = 4" and "y = 1 " ;
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The second "original equation" given is:
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       " -17x = -62 − 6y " ;
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   →    -17(4) = ?  -62  − 6(1) ?

    →  -68 = ? -62 − 6 ?

    →  -68 = ? -68 ?  Yes!
________________________________________________________
The answer is:  {4, 1} .
________________________________________________________
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