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3 years ago

The paragraph below comes from the rental agreement Susan signed when she opened her account at Super Video.

Mathematics

2 answers:

Jobisdone [24]3 years ago

8 0

Answer:

Step-by-step explanation:

i just did the test

NISA [10]3 years ago

7 0

Answer:

option D

Step-by-step explanation:

As per the contract:

"All rentals are due back by midnight of the due date as printed on the transaction receipt. "

In given case clerk did not give any transaction receipt.

so option D is correct

The clerk completed the transaction without giving Susan a receipt or otherwise informing her of the due date !

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22 cups will be left

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Audrey deposited $40,000 in a savings account with simple interest. Five years later, she had earned $30,000 in interest. What w

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$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&\$30000\\ P=\textit{original amount deposited}\dotfill & \$40000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &5 \end{cases} \\\\\\ 30000=(40000)(\stackrel{\%}{\frac{r}{100}})(5)\implies \cfrac{30000}{(40000)(5)}=\cfrac{r}{100}\implies \cfrac{3}{20}=\cfrac{r}{100} \\\\\\ \cfrac{300}{20}=r\implies \stackrel{\%}{15}=r$

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2 years ago

For a segment of a radio show a disc jockey can play 10 records. If there are 12 records to select from in how many ways can the

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Answer:

<h2>66 different ways </h2>

Step-by-step explanation:

This is a combination question. Combination has to do with selection. For example if r objects are to be selected from n pool of oblects, this can be done in nCr number of ways.

nCr = n!/(n-r)r!

According to the question, if a radio show can only play 10 records out of 12 records available, this can be done in 12C10 number of ways.

12C10 = 12!/(12-10)!10!

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3 years ago

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$

therefore

the answer is

$581.25$

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