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svetoff [14.1K]
3 years ago
8

Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!

Mathematics
2 answers:
zmey [24]3 years ago
7 0

Answer by JKismyhusbandbae:

\frac{x}{4}=20\\\mathrm{Multiply\:both\:sides\:by\:}4\\\frac{4x}{4}=20\cdot \:4\\Simplify\\x=80

balandron [24]3 years ago
4 0

remember that you can do anything to an equaiton as long as you do it to both sides

x/4=20

multiiply both sides by 4

4(x/4)=20*4

(x)(4)(1/4)=80

(x)(4/4)=80

x(1)=80

x=80

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10 POINTS + BRAINLIEST TO FIRST CORRECT ANSWER!!! THANK YOU!
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Answer:

The answer is A (Look at the graph of the relationship. Find the y-value of the point that corresponds to x = 1. That value is the unit rate)

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Because the proportional relation is defined by k = \frac{y}{x}. If ratio is \frac{units}{1unit} then it is a rate. Unit rate means per 1 unit such as \frac{amountofmoney}{1kg} or \frac{km}{1hour} thus the correct answer is A.

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2 years ago
A ball is dropped from a height of 192 inches onto a level floor. After the third bounce it is still 3 inches off the ground. Pr
ANEK [815]

Answer: The required fraction = \dfrac18

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Let the required fraction = \dfrac{p}{q}

Given: Initial height = 192 inches

Height of ball after second bounce = \dfrac{p}{q}\times192

Height of ball after third bounce = \dfrac{p}{q}\times\dfrac{p}{q}\times192=192\dfrac{p^2}{q^2}

After the third bounce it is 3 inches off the ground.

So,

(\dfrac{p}{q})^2192=3\\\\\\(\dfrac{p}{q})^2=\dfrac{3}{192}\\\\(\dfrac{p}{q})^2=\dfrac{1}{64}\\\\(\dfrac{p}{q})^2=(\dfrac{1}{8})^2\\\\ \dfrac{p}{q}=\dfrac{1}{8}

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A function is a relation for which each value from the set the first components of the ordered pairs is associated with exactly one value from the set of second components of the ordered pair.

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2 years ago
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