Please help me with this
1 answer:
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Answer:
a) Model
b) The tide will be at 6.5 ft high at 2:24 am (going down).
As the tide will rise again, the tide will be again at 6.5 ft high at 9:36 am (going up).
c) H(10 am) = 7.45
H(4 pm) = 2.55
Step-by-step explanation:
We can model this as a sine or cosine wave, for which we will calculate its parameters by the data given.
The model we will use is:
t will be in hours, starting from midnight (t=0)
1) We know that at midnight happens the high tide. That means that
2) Six hours later (t=6) happens the low tide (0.1 ft)
Now that we have calculated all the parameters, the model for the height of the tide is:
On Feb 10, when is the water level 6.5 feet high?
The tide will be at 6.5 ft high at 2:24 am (going down).
As the tide will rise again, the tide will be again at 6.5 ft high at 9:36 am (going up).
On Feb 10, what is the water level at 10 am? 4pm?
At 10 am is t=10:
At 4 pm, is t=12+4=16
Answer:
2n + 2
Step-by-step explanation:
The formula for nth term of an arithmetic progression is
In this example we have d = 2 (difference, +2 each time) and a1 =4 (first term of sequence).