Question

What is the amplitude of y = 1\2 sin 2x?

Answer 1

Answer:

The amplitude of given function is $\frac{1}{2}$.

Step-by-step explanation:

The given function is

$y=\frac{1}{2}\sin 2x$            .... (1)

The standard form of sine function is

$y=A\sin(Bx+C)+D$              ..... (2)

Where, A is amplitude, $\frac{2\pi}{B}$ is period, C is phase shift and D is mid line.

On comparing (1) and (2), we get

$A=\frac{1}{2}$

Therefore the amplitude of given function is $\frac{1}{2}$.

Answer 2

Hello : 
note : y = A sin(Bx + C) + d       amplitude is A
in this exercise : A =1/2