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ankoles [38]
3 years ago
9

What is the amplitude of y = 1\2 sin 2x?

Mathematics
2 answers:
fomenos3 years ago
8 0

Answer:

The amplitude of given function is \frac{1}{2}.

Step-by-step explanation:

The given function is

y=\frac{1}{2}\sin 2x            .... (1)

The standard form of sine function is

y=A\sin(Bx+C)+D              ..... (2)

Where, A is amplitude, \frac{2\pi}{B} is period, C is phase shift and D is mid line.

On comparing (1) and (2), we get

A=\frac{1}{2}

Therefore the amplitude of given function is \frac{1}{2}.

BARSIC [14]3 years ago
4 0
Hello : 
note : y = A sin(Bx + C) + d       amplitude is A
in this exercise : A =1/2
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