If it takes (a) men (b) hours to dig (c) holes, how many men are required to dig b holes in c hours?

1 answer:

8 0

Well, let's see . . .

You said that (a) men can dig (c) holes in (b) hours.

So . . . It takes (a) men (b / c) hours to dig one hole.

And . . . It takes One man (a b / c) hours to dig one hole.

Now . . . There are (b) holes to be dug.

    It would take one man (a b / c)·(b) = (a b² / c) hours to dig them all.

But if you had 'x' men, it would only take them (c) hours to do it.

So    c = (a b² / c) / x

   x c = (a b² / c)

   x = a b² / c² men .

Now, I lost the big overview while I was doing that,
and just started following my nose through the fog.
So I have to admit that I'm not that confident in the answer.
But gosh durn it. That's the answer I got, and I'm stickin to it.
Rrarrup !

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8.EE.5

olga2289 [7]

Answer:

1.) $slope=2$

2.) $slope=-3$

3.) $slope=\frac{1}{4}$

4.) $slope=-\frac{4}{5}$

Step-by-step explanation:

The unit rate is also known as slope. Slope is the change in the y values over the change in the x values:

$(x_{1},y_{1})\\\\(x_{2},y_{2})\\\\\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=slope$

However, with certain graphs, the slope can be found in a simpler manner.

You start at one point and move across the y-axis, then move along the x-axis until you reach another point on the same line.

Make sure you move on the y-axis first, then the x-axis. Record the slope as spaces moved in each $\frac{y}{x}$

When you move up, the number will be positive $(\frac{+y}{x})$ . If you move down, the number will be negative $(\frac{-y}{x})$ .
If you move to the right, the number will be positive $(\frac{y}{+x})$ . If you move to the left, the number will be negative $(\frac{y}{-x})$ .