If it takes (a) men (b) hours to dig (c) holes, how many men are required to dig b holes in c hours?

1 answer:

8 0

Well, let's see . . .

You said that (a) men can dig (c) holes in (b) hours.

So . . . It takes (a) men (b / c) hours to dig one hole.

And . . . It takes One man (a b / c) hours to dig one hole.

Now . . . There are (b) holes to be dug.

    It would take one man (a b / c)·(b) = (a b² / c) hours to dig them all.

But if you had 'x' men, it would only take them (c) hours to do it.

So    c = (a b² / c) / x

   x c = (a b² / c)

   x = a b² / c² men .

Now, I lost the big overview while I was doing that,
and just started following my nose through the fog.
So I have to admit that I'm not that confident in the answer.
But gosh durn it. That's the answer I got, and I'm stickin to it.
Rrarrup !

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Hey:) can you please help me posted picture of question

mr Goodwill [35]

The top row contains the product of $x^{2}$ with each term of the expressions $x^{6}+ x^{4}+ x^{2}$ and bottom row contains the product of -1 with each term of expression $x^{6}+ x^{4}+ x^{2}$ .

The final result will be the sum of terms of both rows as shown below:

$( x^{6}+ x^{4} + x^{2} )( x^{2} -1) \\ \\ 
= x^{2} ( x^{6}+ x^{4} + x^{2} )-1( x^{6}+ x^{4} + x^{2} ) \\ \\ 
= x^{8}+ x^{6}+ x^{4}- x^{6}- x^{4}- x^{2} \\ \\ 
= x^{8}- x^{2}$

So the correct answer is option D

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suter [353]

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A) 2(8+6)

2(14)

B) 2(12+4)

2(16)

C) 6*8

D) 12*4

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