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3 years ago

Please solve quick!! i really need it!!

Mathematics

1 answer:

sveticcg [70]3 years ago

7 0

Answer:

$\dfrac{1}{x^2}+\dfrac{y^2}{x^4}$

Step-by-step explanation:

Separate the fraction(s) at the plus sign and simplify.

$\dfrac{x^2+y^2}{x^4}=\dfrac{x^2}{x^4}+\dfrac{y^2}{x^4}\\\\=\dfrac{1}{x^2}+\dfrac{y^2}{x^4}$

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2 years ago

2.<br> Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?

mezya [45]

Answer:

the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

Step-by-step explanation:

We need to find inverse of the quadratic function $f(x) = x^2 - 3$

Let

$y=x^2-3$

Replace x and y

$x=y^2-3$

Now, we will solve for y

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$x+3=y^2-3+3$

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Taking square root on both sides

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Now replace y with $f^{-1}(x)$

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2 years ago

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Ivenika [448]

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