Question

Please help, due today.

Answer 1

Hi there
I know it is!

Answer 2

Quadratic formula: $x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$     [ +/-   is   ± ]    

You can find the value of a, b, c  -->  ax² + bx + c = 0  

$x=\frac{-2+/-\sqrt{2^2-4(1)(-4)} }{2(1)}$    Since this is not simplified, you can find a, b, c:

a = 1

b = 2

c = -4

A.)  x² + 1 = 2x − 3   Make the equation into ax² + bx + c = 0. Subtract 2x on both sides, and add 3 on both sides to set the equation equal to 0

x² + 1 - 2x + 3 = 2x - 2x - 3 + 3

x² - 2x + 4 = 0      

a = 1

b = -2

c = 4    This is not the answer because b = 2 not -2, and c = -4 not 4

B.) x² - 2x − 1 = 3     Subtract 3 on both sides to set the equation = 0

x² - 2x - 4 = 0

a = 1

b = -2

c = -4      This is not the answer because b = 2 not -2

C. x² + 2x - 1 = 3    Subtract 3 on both sides to set the equation = 0

x² + 2x - 4 = 0

a = 1

b = 2

c = -4    This is your answer

D. x² + 2x - 1 = -3      Add 3 on both sides to set the equation = 0

x² + 2x + 2 = 0

a = 1

b = 2

c = 2       This is not the answer because c = -4 not 2